在Android的资源动态无命名则getIdentifier [英] Dynamic naming of Resources in Android without getIdentifier

问题描述

我使用的OpenGL ES以使Android的游戏。我从一个教程约code和我试图去改变它适合我的应用程序，但我有一个问题。我想用传递给函数的资源名称的字符串动态获取的图像资源。通常我知道你在这种情况下使用则getIdentifier（），但返回一个int，我需要的输入流。有没有从资源动态？

获得的输入流中的任何方式

另外，有这样做的更好的办法？

code如下：

  InputStream为= mContext.getResources（）openRawResource（R.drawable＆LT; imagename＆GT;）。位图位图;
尝试{
      位= BitmapFactory.de codeStream（是）;
}
最后{
      尝试{
            is.close（）;
      }
      赶上（IOException异常五）{
            e.printStackTrace（）;
      }
}
 

解决方案

是U可以假设u必须与命名IMG1，IMG2，IMG3，IMG4，IMG5，img6，IMG7比存储在图像绘制
首先要像

数组

 的String [] = imgarray {IMG1，IMG2，IMG3，IMG4，IMG5，img6，IMG7};
公共静态字符串PACKAGE_NAME;
PACKAGE_NAME = getApplicationContext（）getPackageName（）。
随机R =新的随机（）;
INT N = r.nextInt（imgarray.length（））;
INT渣油= getResources（）则getIdentifier。（PACKAGE_NAME +：绘/+ imgarray [N]，NULL，NULL）;
imageview.setImageResource（渣油）;
 

如果要位图图像，不仅仅是在下面添加行

 位图BM = BitmapFactory.de codeResource（getResources（），渣油）;
 

如果ü希望用更少的编码其他方式比看到<一个公认的答案href=\"http://stackoverflow.com/questions/10135713/display-a-random-image-when-a-button-is-clicked/10135994#10135994\">Other例如

I'm using OpenGL ES to make a game in Android. I got some code from a tutorial and I'm trying to change it to suit my app but I'm having a problem. I want to dynamically get an image resource using a string passed into a function as the resource name. I know usually you use getIdentifier() in this case, but that returns an int and I need an input stream. Is there any way of getting an input stream from a resource dynamically?

Alternatively, is there a better way of doing this?

Code below:

InputStream is = mContext.getResources().openRawResource(R.drawable.<imagename>);

Bitmap bitmap;
try {
      bitmap = BitmapFactory.decodeStream(is);
}
finally {
      try {
            is.close();
      } 
      catch (IOException e) {
            e.printStackTrace();
      }
}

解决方案

yes u can Suppose u have images stored in drawable with naming img1,img2,img3,img4,img5,img6,img7 than first make an array like

String[] imgarray={"img1","img2","img3","img4","img5","img6","img7"};
public static String PACKAGE_NAME ;
PACKAGE_NAME=getApplicationContext().getPackageName();
Random r = new Random();
int n=r.nextInt(imgarray.length());
int resID = getResources().getIdentifier( PACKAGE_NAME+":drawable/" +imgarray[n] , null, null);  
imageview.setImageResource(resID);

if want bitmap image than just add below line

Bitmap  bm = BitmapFactory.decodeResource(getResources(),resID);

if u want other way with less coding than see accepted answer at Other Example

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