在MIPS中向左移动 [英] Shifting left in MIPS

问题描述

在方法一中，我想将要转移的数字存储在$ a0内部(例如5位)，并且我想将$ t9转移5位，但是我遇到了麻烦.有人知道为什么吗?

In my method one, I have the number that I want to shift by stored inside $a0 (e.g. 5 bits), and I want to shift $t9 by 5 bits, but I'm running into a bit of trouble. Does anyone know why?

MethodOne:

sw $a0, ($t8)
sll $t9, $t9, $t8

推荐答案

要向左移动可变量，请使用sllv:

To shift left by a variable amount, use sllv:

sllv $t9, $t9, $a0

sll仅占用立即移位量.不需要sw或$t8.

sll only takes an immediate shift amount. There is no need for sw or $t8.

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