MIPS:写入和读取文件 [英] MIPS: Write AND read a file

问题描述

我正在尝试在MIPS中合并两个不同的程序，以便在文件上写入内容，然后通过简单的菜单进行读取. 写作做得很好，流畅.阅读有点麻烦，因为我看不到任何输出.如果与写作部分分开，则阅读部分本身可以工作. 有人可以告诉我我做错了什么吗? 谢谢！

I'm trying to merge two different programs in MIPS in order to write something on a file and then read it through a simple menu. Writing is done good and smooth. Reading is a bit more problematic, since I can't see any output. The reading part itself works, if separated from the writing part. Can someone enlight me on what I'm doing wrong? thanks!

<pre>

.data

fout: .asciiz "test.txt"
reservedspace: .space 1024
cont: .asciiz "reading file... "

buffer: .asciiz "some text to test the program."
##################################################

.text 

main:

menu:

getinput:   

li $v0, 5
syscall
move $s0, $v0

beq $s0, 0, create  
beq $s0, 1, read    
beq $s0, 2, delete
beq $s0, 3, show
beq $s0, 4, exit

j getinput

#######################################

create:
    #write on file
    #open
    li $v0, 13
    la $a0, fout
    li $a1, 1
    li $a2, 0
    syscall
    move $s6, $v0

    #write
    li $v0, 15
    move $a0, $s6
    la $a1, buffer
    li $a2, 30
    syscall

    #close
    li $v0, 16
    move $a0, $s6
    syscall
j menu

search:
    li $v0, 13
    la $a0, fout
    li $a1, 0
    li $a2, 0
    syscall
    move $s6, $v0

    li $v0, 14
    move $a0, $s6
    la $a1, reservedspace
    li $a2, 1024
    syscall

    li  $v0, 4
    la  $a0, cont
    syscall

    close:
    li $v0, 16
    move $a0, $s6
    syscall
j menu

delete:
show:
exit:

    li $v0, 10          #Terminate Program
    syscall

<code>

推荐答案

由于未打印已阅读的内容，因此看不到任何输出. 从文件中读取文本后，应将其存储在您提供的缓冲区(reservedspace)中. 因此，例如，您可以使用以下命令打印该缓冲区的内容:

You are not seeing any output because you are not printing what you have read. After reading the text from the file it should be stored in the buffer you provided (reservedspace). So, you can for example print the contents of that buffer with

  la $a0, reservedspace
  li  $v0, 4
  syscall

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