摩卡:具有特定参数的存根方法，但不适用于其他参数 [英] Mocha: stubbing method with specific parameter but not for other parameters

问题描述

我只想在给定特定参数值时使用Mocha存根方法，而在给定其他任何值时调用原始方法.

I want to stub a method with Mocha only when a specific parameter value is given and call the original method when any other value is given.

当我这样做时:

MyClass.any_instance.stubs(:show?).with(:wanne_show).returns(true)

我得到

unexpected invocation for MyClass.show?(:other_value)

我也知道，在编写模拟时，可以在不进行"with"调用的情况下对所有参数进行存根，然后给出我的特定模拟.但是然后我必须知道每个调用的返回值，情况并非如此:/

I also know, that I can stub all parameters when writing the mock without the ´with´-call and then give my specific mock. But then I have to know the return value for every call, which is not the case :/

tldr; 是否可以在存根中调用原始方法或仅存入特定参数并保留其他参数?

tldr; Is there a way to call the original method in a stub or to stub just specific parameters and leave the others?

推荐答案

答案取决于您要测试的内容.

The answer depends on what exactly you're testing.

一些注意事项:

1)我总是避免使用stubs.any_instance.您可以在存根/模拟中具体说明，这可以防止错误的测试阳性结果.

1) I always avoid using stubs.any_instance. You can be specific in your stubs/mocks, which prevents false testing positives.

2)我更喜欢将间谍与存根一起使用，以主动断言某些东西已经被调用.为此，我们使用 bourne gem.另一种方法是使用模拟程序，它隐式测试是否正在调用某些东西(例如，如果不被调用，将会失败.

2) I prefer using spies along with stubs, to actively assert that something has been called. We use the bourne gem for this purpose. The alternative is to use a mock, which implicitly tests if something is being called (e.g. will fail if it doesn't get called.

所以您的类方法可能看起来像这样(注意，这是RSpec语法):

So your class-method might looks something like this (note, this is RSpec syntax):

require 'bourne'
require 'mocha'

it 'calls MyClass.show?(method_params)' do
  MyClass.stubs(:show?)

  AnotherClass.method_which_calls_my_class

  expect(MyClass).to have_received(:show?).with('parameter!')
end

class AnotherClass
  def self.method_which_calls_my_class
    MyClass.show?('parameter!')
  end
end

有很多存根/间谍示例此处.

There are a lot of stub/spy examples here.

希望这会有所帮助.

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