Python模拟补丁另一个函数中的一个函数 [英] Python mock patch a function within another function
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问题描述
def f1():
return 10, True
def f2():
num, stat = f1()
return 2*num, stat
如何使用python的模拟库修补f1()
并返回自定义结果,以便我可以测试f2()
?
How do I use python's mock library to patch f1()
and return a custom result so I could test f2()
?
已 我的考试有问题吗?这似乎不起作用,所有测试均因AssertionError失败
Edited: Is there something wrong with my test? This doesn't seem to be working, all the tests failed with AssertionError
from foo.bar import f2
from mock import patch
class MyTest(TestCase):
def test_f2_1(self):
with patch('project.module.f1') as some_func:
some_func.return_value = (20, False)
num, stat = f2()
self.assertEqual((num, stat), (40, False))
@patch('project.module.f1')
def test_f2_2(self, some_func):
some_func.return_value = (20, False)
num, stat = f2()
self.assertEqual((num, stat), (40, False))
推荐答案
第一个示例建议f1()和f2()在同一模块中定义. 因此,以下方法应该起作用:
First example suggests that f1() and f2() defined in the same module. Hence the following should work:
from foo.bar import f2
from mock import patch
class MyTest(TestCase):
@patch('foo.bar.f1')
def test_f2_2(self, some_func):
some_func.return_value = (20, False)
num, stat = f2()
self.assertEqual((num, stat), (40, False))
补丁与导入相同:@patch('foo.bar.f1')
这是一个很好的答案:
http://bhfsteve. blogspot.nl/2012/06/patching-tip-using-mocks-in-python-unit.html
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