在python上模拟超类调用 [英] Mocking the super class calls on python
本文介绍了在python上模拟超类调用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在做一些单元测试,有时需要模拟super
调用以引发错误,例如:
I am doing some unit testing and at some point I need to mock a super
call to throw an error, for example:
@classmethod
def myfunc(cls, *args, **kwargs)
try:
super(MyClass, cls).my_function(args, kwargs)
except MyException as e:
#...
我通常使用 mocker 库来模拟我的对象,但是我还没有找到模拟该对象的方法
I am using the mocker library to mock my objects in general but I haven't found a way to mock this.
推荐答案
我发现了一种方法,虽然有点hacky,但是可以用,我将以我的示例为例进行说明,这是基于
I found a way, sort of hacky but it works, I'll explain with my example, this is based on this response so thanks @kindall:
def my_test(self):
import __builtin__
from mocker import Mocker, KWARGS, ARGS
mymocker = mocker.mock()
mymocker.my_function(ARGS, KWARGS)
mocker.throw(MyException)
def mysuper(*args, **kwargs):
if args and issubclass(MyClass, args[0]):
return mymocker
return original_super(*args, **kwargs)
__builtin__.original_super = super
__builtin__.super = mysuper
with mocker:
MyClass.myfunc()
所以从本质上讲,我要做的是检查super
调用是否来自我要模拟的类,否则只需执行常规的super
.
so essentially what I do is check if the super
call is from the class I want to mock, else just do a normal super
.
希望这对某人有帮助:)
Hope this helps someone :)
这篇关于在python上模拟超类调用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文