PHPUnit:存根方法未定义 [英] PHPUnit: stub methods undefined

问题描述

我一定很想念东西.我正在尝试在PHPUnit中的类上对方法进行存根，但是当我在模拟对象上调用该方法时，它告诉我该方法未定义.

I must be missing something. I'm trying to stub methods on a class in PHPUnit, but when I invoke the method on the mock object, it tells me that method is undefined.

存根示例类:

namespace MyApp;

class MyStubClass 
{
   public function mrMethod()
   {
     // doing stuff
   }   
}

要存根，我写:

// specifying all getMock() args to disable calling of class __construct()
$stub = $this->getMock('MyStubClass', array(), array(), 'MockMyStubClass', false, false, false);
$stub->expects($this->any())
     ->method('mrMethod')
     ->will($this->returnValue('doing stuff'));

但是在调用存根方法时，我得到了一个例外:

But upon invoking the stubbed method, I get an exception:

$stub->mrMethod();
//PHP Fatal error:  Call to undefined method MockMyStubClass::mrMethod()

我正在将PHPUnit 3.4.3与PHP 5.3.0结合使用.

I'm using PHPUnit 3.4.3 with PHP 5.3.0.

我注意到的另一件事是，如果在getMock()方法中指定名称空间，则由于存在双重名称空间而导致类加载异常:

Another small thing I noticed was that if specifying a namespace in the getMock() method results in a class loading exception because of a double namespace:

$stub = $this->getMock('MyApp\MyStubClass');
// Fatal error:  Class 'MyApp\MyApp\MyStubClass' not found

这让我感到很奇怪(并且getmock()将不接受带有前导反斜杠的名称空间).我唯一想到的原因可能是因为该类是 在自动装带器上注册?

That strikes me as rather odd (and getmock() will not accept a namespace with a leading backslash). The only thing I could think to cause that would may be because this class is registered with an autoloader?

有什么想法吗?

推荐答案

回答我自己的问题:

经过很多挫折之后，我确实设法使事情开始了.我不确定问题到底是什么，但是确实发现了一些可能对其他人有帮助的事情:

After quite a bit of frustration, I did manage to get things working. I'm not sure precisely what the issue was, but did discover a few things that might help others:

• 确保您正在运行最新版本的PHPUnit(在撰写本文时为3.4.6)

• 使用完全限定的名称空间减去第一个反斜杠.

• Make sure you're running the latest version of PHPUnit (3.4.6 as of this writing)

• Use the fully-qualified namespace minus the first backslash.

$this->getMock('MyApp\Widgets\WidgetFactory');

我的问题的一部分是PHPUnit正在创建一个存根类WidgetFactory，而该存根类实际上并未存根MyApp\Widgets\WidgetFactory.人们会希望，如果尝试对不存在的类进行存根，则会发生异常，但似乎不会因名称空间混乱而发生.

Part of my problem was that PHPUnit was creating a stub class WidgetFactory that was not actually stubbing MyApp\Widgets\WidgetFactory. One would expect that an exception would occur if trying to stub a non-existent class, but it doesn't seem to happen with the namespace confusion.

此外，在此处上存在一个问题，建议使用以下类别名方法:

Also, there is a question over here that suggests using the class alias method as follows:

    class_alias('MyApp\Widgets\WidgetFactory', 'WidgetFactory');
    $this->getMock('WidgetFactory');

虽然这确实可以暂时解决我的问题，但我强烈建议您不要使用它. class_alias()对于相同的别名，不能在没有引发异常的情况下被两次调用，如果在setup()方法中使用或作为存根生成的一部分，则会导致明显的问题.

While this did temporarily solve my problem, I would strongly advise against using it. class_alias() cannot be called twice for the same alias without raising an exception, which causes obvious problem if used in the setup() method, or as part of the stub generation.

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