Python模拟:如何测试是否调用了super() [英] Python-mock: how to test if super() was called

问题描述

我具有以下结构:

class A(Object):
    def method(self):
        return 'a'

class B(A):
   def __init__(self, test):
       self.test = test

   def method(self):
        if self.test:
           return super(A, self).method(self)
        else:
           return 'b'

我想做的是编写一个测试用例，用于测试self.test是否为true，然后调用超级函数，并调用A类的方法函数.

What I want to do is write a test-case which would test that if self.test is true then the super function was called and class A's method function was called.

我该如何实现?我该嘲笑什么?

How I can achieve this? What should I mock?

高级问:当A类和B类位于单独的模块中并且它们具有相同的名称时，该怎么办? 因此，我将代替类B编写:类A(module1.A): 会改变嘲笑吗?

Advanced Q: What about when Class A and B are in a separate module, and they have the same name. So instead of class B I would write: class A(module1.A): does that change the mocking?

推荐答案

@MartijnPieters 指出，正在测试所谓的超级通常是对实现细节的测试，而不是合同的测试.尽管如此，仍然可能需要测试特定的实现-否则父类可能具有要求调用super的合同.要测试是否调用了super，请使用模拟程序，如 @mgilson 所述.详细的答案:

As @MartijnPieters points out, testing that super is called is typically a test of an implementation detail, rather than a test of a contract. Nonetheless, testing the specific implementation may still be desirable -- or the parent class may have a contract requiring the call to super. To test that super is called, use a mock, as mentioned by @mgilson. The answer in detail:

import mock, unittest

class TestB(unittest.TestCase):

    @mock.patch("A.method")
    def test_super_method(self, mock_super):
        B(True).method()
        self.assertTrue(mock_super.called)

    @mock.patch("A.method")
    def test_super_method(self, mock_super):
        B(False).method()
        self.assertFalse(mock_super.called)

您需要在补丁中指定完整的名称空间.例如@mock.patch("module.submodule.A.method").可以对A中的任何方法(包括__init__)进行此操作.语法完全一样.

You'll need to specify the full namespace in the patch. E.g., @mock.patch("module.submodule.A.method"). This can be done for any method in A, including __init__; syntax is exactly the same.

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