只需单击按钮即可打开模态 [英] opening a modal with the click of a button

问题描述

下面的代码使用Modal react组件:

The next code uses a Modal react component:

export class AddWorkLogEditor extends React.Component {
    constructor(props) {
        super(props);

        this.addWorkLog = this.addWorkLog.bind(this);       
        this.onOpenModal = this.onOpenModal.bind(this);
        this.onCloseModal = this.onCloseModal.bind(this);
        this.state = {
             open:true

           };
      }

  onOpenModal() {
     this.setState({open: this.props.openModal});
  }

  onCloseModal() {
     this.setState({open:false});
  }

  addWorkLog() {

   }



 render() {
      const bstyle = {
         backgroundColor: 'green',
         textAlign:"left",
         paddingLeft: '0px',
         color: 'white'
    };
 const {open} = this.state;
       return (
           <div>
                <Modal open={open} onClose={this.onCloseModal} little>
                <h3>hi gi</h3>

                 <Button bsStyle="success" bsSize="small" onClick ={(ev) => {console.log(ev)} }> Save </Button>
                 </Modal>
            </div>
       );
    }
}

我正试图使用​​:

addWorkLog()
{
      return <AddWorkLogEditor/>;
}

和

 createAddWorkLogButton () {

    return (
        <button style={ { color: '#007a86'} } onClick={this.addWorkLog} >Add Work Log</button>
    );
 }

我的意思是，当我单击此按钮后，什么都没有显示.还有另一种方法可以调用该模式吗?我从以下位置导入模式:

I mean, after I click at this button nothing shows up. Is there another way to call that modal? I am importing the modal from:

从反应模式"中导入模态

import Modal from 'react-responsive-modal'

推荐答案

您试图仅在单击按钮后才渲染模态，这对于非反应性环境来说是很自然的，但在反应中它会以不同的方式起作用.在最简单的解决方案中，应始终呈现Modal，并且当用户单击按钮时，将模式open属性更改为true.

You are trying to render the modal only once the button is clicked, while that's quite natural for non-react environments, in react it works in a different way. In the simplest solution the Modal should be always rendered, and when a user clicks the button you change the modal open property to true.

{ /* all the markup of your page */ }
<button onClick={() => this.setState({showModal: true})}>Add Work Log</button>
{ /* anything else */ }

{ /* modal is here but it is hidden */ }
<Modal open={this.state.showModal}>...</Modal>

或者，您可以完全跳过模式渲染，直到showModal变为true.

Alternatively, you can just skip the modal rendering at all until the showModal becomes true.

this.state.showModal && <Modal open>...</Modal>

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