如何从源模型获取索引行号 [英] How to get Index Row number from Source Model

查看:164
本文介绍了如何从源模型获取索引行号的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

点击QTableView" Item_B_001 ",将打印出其行号# 0 .

Clicking the QTableView "Item_B_001" prints out its row number # 0.

但是在源模型的self.items中,该项目对应于数字#3.如何获取真实"源模型的项目的行号-它确实与之对应的数字?

But in source model's self.items this item corresponds to the number # 3. How to get a "real" Source Model's Item's row number - a number it really corresponds to?

from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys

class Model(QAbstractTableModel):
    def __init__(self, parent=None, *args):
        QAbstractTableModel.__init__(self, parent, *args)
        self.items = ['Item_A_001','Item_A_002','Item_B_001','Item_B_002']

    def rowCount(self, parent=QModelIndex()):
        return len(self.items)       
    def columnCount(self, parent=QModelIndex()):
        return 1

    def data(self, index, role):
        if not index.isValid(): return QVariant()
        elif role != Qt.DisplayRole:
            return QVariant()

        row=index.row()
        if row<len(self.items):
            return QVariant(self.items[row])
        else:
            return QVariant()

class Proxy(QSortFilterProxyModel):
    def __init__(self):
        super(Proxy, self).__init__()

    def filterAcceptsRow(self, row, parent):
        if '_B_' in self.sourceModel().data(self.sourceModel().index(row, 0), Qt.DisplayRole).toPyObject():
            return True
        return False

class MyWindow(QWidget):
    def __init__(self, *args):
        QWidget.__init__(self, *args)

        tableModel=Model(self)               

        proxyModel=Proxy()
        proxyModel.setSourceModel(tableModel)

        self.tableview=QTableView(self) 
        self.tableview.setModel(proxyModel)
        self.tableview.clicked.connect(self.viewClicked)
        self.tableview.horizontalHeader().setStretchLastSection(True)

        layout = QVBoxLayout(self)
        layout.addWidget(self.tableview)
        self.setLayout(layout)

    def viewClicked(self, indexClicked):
        print 'index of proxy row', indexClicked.row()

if __name__ == "__main__":
    app = QApplication(sys.argv)
    w = MyWindow()
    w.show()
    sys.exit(app.exec_())

推荐答案

我认为您可以使用QAbstractProxyModel::mapToSource()函数在源模型中返回与代理模型中的索引相对应的模型索引. IE. (不确定Python语法):

I think you could use the QAbstractProxyModel::mapToSource() function to return the model index in the source model that corresponds to the index in the proxy model. I.e. (not sure about Python syntax):

def viewClicked(self, indexClicked):
    print 'index of proxy row', self.proxyModel.mapToSource(indexClicked).row()

这篇关于如何从源模型获取索引行号的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆