Titanium保存上次查看窗口的状态 [英] Titanium Saving the state of the last window viewed

问题描述

我该如何保存应用程序最后一次查看的窗口的状态?

How would i go about saving the state of the last viewed window of my application?

我一直在尝试Titan.app.properties，但是没有运气.我正在使用MVC，所以所有内容都被拆分成单独的文件.我会在模型中创建几个全局变量，然后使用app.properties调用它们来解决这个问题吗?如果可以提供帮助，请您举个例子吗?

I have been trying titanium.app.properties with no luck. I am using MVC so everything is split up into separate files. Would I go about this by making a couple of global variables in the model, and calling them with app.properties? If you can help, could you please provide an example?

感谢您的帮助< 3

Thanks for any help <3

推荐答案

因此，我已经能够通过简单地按照另一个答案中的说明进行操作.给任何有兴趣的人

So i have been able to get it to work by simply doing as stated in another answer. for anyone interested It goes as follows

//This decides what screen it should open
var lastwin = Ti.App.Properties.getString("lastwin");

if ( lastwin == 'SavedList'){
    SavedList.open();
    SavedListNav.open();
}
else if (lastwin == 'tomList'){
    tomList.open();
    TomNav.open();
}
else if (lastwin == 'Recipes'){
    Recipes.open();
    RecipesNav.open();
}
else MainMenu.open();

//in each function that leads to the specific screen you want do it like so
SavedListsBTN.addEventListener('click', function(e){
    Ti.App.Properties.setString("lastwin", 'SavedList');
    SavedList.open();
    SavedListNav.open();
    MainMenuNav.close();
    MainMenu.close();
});

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