Web方法返回正常，但触发失败功能 [英] Web method return OK but fire fail function

问题描述

这是我的网络方法

[HttpGet]
        public ActionResult EditEmp(int? id)
        {
            if (id == null)
            {
                return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
            }
            Employee Emp = db.Employees.Find(id);
            if (Emp == null)
            {
                return HttpNotFound();
            }
            ViewBag.dept_id = new SelectList(db.Departments, "dept_id", "dept_name", Emp.dept_id);
          return PartialView("_EditEmp", Emp);
        }   

这是ajax调用

 $.ajax({
                    type: "GET",
                    url: '/Employee/EditEmp',
                    data: { id: idp },
                    dataType: "json",
                    success: function (result) {        
                        alert(result);
                        $('#editid').html(result);

                    },
                    error: function (result) {
                        alert("FAILED : " + result.status + ' ' + result.statusText);                     
                    }

                });

它给了我result.status = 200和result.statusText = OK，但它引发了错误事件

it gives me result.status =200 and result.statusText = OK but it fire Error Event

推荐答案

请检查您是否返回了有效的json，因为您正在设置

Please check that you are returning valid json or not, because you are setting

dataType:"json"

dataType: "json"

它将响应评估为JSON并返回一个JavaScript对象. (...)严格解析JSON数据；任何格式错误的JSON都会被拒绝，并引发解析错误.

it evaluates the response as JSON and returns a JavaScript object. (...) The JSON data is parsed in a strict manner; any malformed JSON is rejected and a parse error is thrown.

您可能想看看此

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