是否有可能使正则表达式中的字符无效 [英] Is it possible to make ineffective a character in regex

问题描述

我正在尝试编写wordpress漂亮的永久链接正则表达式.

I'm trying to write wordpress pretty permalinks regex.

我有以下网址.我需要2场比赛，

I have following urls. I need 2 matches,

1st:/和/之间的最后一个字，在get/之前 2nd:以get/开头的字符串 网址可能是这样的

1st : last word between / and / before get/ 2nd : string which is start with get/ Url's may be like these

http://localhost/akasia/yacht -technical-services/游艇船员/get/gulets/for/sale/

在这里，我需要游艇船员"和获取/gulets/出售/出售/"

Here I need "yacht-crew" and "get/gulets/for/sale/"

http://localhost/akasia/testimonials/get/motoryachts/for/sale /

在这里我需要推荐"并获得/摩托车/用于/出售/

here I need "testimonials" and get/motoryachts/for/sale/

http://localhost/akasia/may/be/lots/of/seperator/but/ineed/last/get/ships/for/rent/

在这里我需要最后一个"并获得/发货/获得/租金/

here I need "last" and get/ships/for/rent/

$url1 = 'somepage/get/gulets/for/sale'; // I need somepage and get/gulets/for/sale
$url2 = 'somepage/subpage/get/motoryachts/for/rent'; // I need subpage and get/motoryachts/for/rent
$url3 = 'may/be/unlimited/directories/but/i/need/here/get/ships/for/sale'; // I need here and get/ships/for/sale
$url4 = 'services/get/gulets/for/sale'; // I need services and get/gulets/for/sale
$regex = '([^\/]+?)\/(get\/.+)';

// I can not change anything below.
preg_match("#^$regex#", $url4, $matches);
echo "<pre>";
print_r($matches);
echo "</pre>"

我捕获了$ url4，但无法获取$ url1，$ url2，$ url3

I catch $url4 but Could not $url1, $url2, $url3

如果有人帮忙，我会感激不尽.

I appreciate if someone help.

推荐答案

使用\K丢弃先前匹配的字符，使其从最终打印中消失.

Use \K to discard the previously matched characters from printing at the final.

.*(?:\/|^)\K([^\/]+?)\/(get\/.+)

演示

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