如何删除不需要的字符串中的字符 [英] How to remove unwanted characters in a string

问题描述

您好，我从服务器获取JSON响应。我解析它。但是从响应字符串看起来像这样

hi I am getting a json response from the server. I parsed it . but the String from the response looked like this

＆roominfo LT; BR /＆GT;＆LT; BR /＆GT; ＆LT; P＆GT;＆LT;强＆GT;声明：＆LT; / STRONG＆GT;＆LT; BR /＆GT;＆LT; / P＆GT;＆LT; P＆GT;＆LT; UL＆GT;＆LT;李＆gt;一种度假费已包含在总价＆LT ; /李＆GT; ＆所述; / UL＆GT;＆下; / P＆GT;＆所述p为H.;＆下; / P＆GT;＆所述p为H.;＆下; / P＆GT; ＆LT; P＆gt;在以下费用和押金由酒店在提供服务时收取，办理入住或退房手续。 ＆LT; UL＆GT;＆LT;李＆GT;代客停车费用：每晚USD30（中/自由进出）LT; /李＆GT;＆LT;李＆GT;宠物费：45美元每次住宿＆LT; /李＆GT;＆LT;李＆GT;无线上网费用所有公共区域：USD 11.95（包24小时，费率可能会发生变化）＆LT; /李＆GT;＆LT;李＆GT;费用室内无线上网费用：11.95（包24小时，费率可能会发生变化）＆LT; /李＆GT; ＆所述; / UL＆GT;＆下; / P＆GT;＆所述; P＆gt;将上面所列可能并不玉米prehensive。这些费用和押金可能不包括税款，并且有可能发生变化。 ＆LT; / P＆GT;

roominfo<br /><br /> <p><strong>Notifications and Fees:</strong><br /></p><p><ul><li>A resort fee is included in the total price displayed</li> </ul></p><p></p><p></p> <p>The following fees and deposits are charged by the property at time of service, check-in, or check-out. <ul><li>Valet parking fee: USD 30 per night (in/out privileges)</li><li>Pet fee: USD 45 per stay</li><li>Fee for wireless Internet in all public areas: USD 11.95 (for 24 hours, rates may vary)</li><li>Fee for in-room wireless Internet: USD 11.95 (for 24 hours, rates may vary)</li> </ul></p><p>The above list may not be comprehensive. Fees and deposits may not include tax and are subject to change. </p>

如何从这个字符串删除不需要的字符

how to remove the unwanted characters from this string

推荐答案

如果您不需要的角色是 HTML 标签然后用这个

If your unwanted character are HTML tags then use this

 String noHTMLString = htmlString.replaceAll("\\<.*?>","");

它使用一个普通的前pression来移除封闭括号的任何文字。

It uses a regular expression to remove any text that is enclosed with brackets.

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