Ruby Modulo部门 [英] Ruby Modulo Division

问题描述

所以我制作了一个程序，使用模块在Ruby中进行模除:

So I made a program to do modulo division in Ruby, using a module:

module Moddiv
    def Moddiv.testfor(op1, op2)
        return op1 % op2
    end
end

程序:

require 'mdivmod'
print("Enter the first number: ")
gets
chomp
firstnum = $_
print("Enter the second number: ")
gets
chomp
puts
secondnum = $_
puts "The remainder of 70/6 is " + Moddiv.testfor(firstnum,secondnum).to_s

当我用两个数字(例如70和6)运行它时，我得到70作为输出！为什么会这样?

When I run it with two numbers, say 70 and 6, I get 70 as the output! Why is this happening?

推荐答案

这是因为firstnum和secondnum是字符串 "70"和"6".并定义了String#%-它是格式化输出运算符.

It's because firstnum and secondnum are the strings "70" and "6". And String#% is defined - it's the formatted-output operator.

由于"70"不是格式字符串，因此将其视为文字.因此"70" % "6"打印根据模板"70"格式化的"6"，该模板就是"70".

Since "70" is not a format string, it's treated as a literal; so "70" % "6" prints "6" formatted according to the template "70", which is just "70".

您需要使用firstnum = $_.to_i等转换输入.

You need to convert your input with firstnum = $_.to_i etc.

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