监控ZIP文件提取Python [英] Monitor ZIP File Extraction Python

问题描述

我需要解压缩.ZIP存档.我已经知道如何解压缩它，但是它是一个巨大的文件，需要一些时间才能解压缩.我如何打印提取完成的百分比?我想要这样的东西:

I need to unzip a .ZIP archive. I already know how to unzip it, but it is a huge file and takes some time to extract. How would I print the percentage complete for the extraction? I would like something like this:

Extracting File
1% Complete
2% Complete
etc, etc

推荐答案

以下是您可以优化的示例:

here an example that you can start with, it's not optimized:

import zipfile

zf = zipfile.ZipFile('test.zip')

uncompress_size = sum((file.file_size for file in zf.infolist()))

extracted_size = 0

for file in zf.infolist():
    extracted_size += file.file_size
    print "%s %%" % (extracted_size * 100/uncompress_size)
    zf.extract(file)

为了使其更美观，请在打印时执行以下操作:

to make it more beautiful do this when printing:

 print "%s %%\r" % (extracted_size * 100/uncompress_size),

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