如何使用Firebug的Monitor(fn)? [英] How to use Firebug's monitor(fn)?

问题描述

我阅读了有关命令行API 的Firebug文档.

I read the Firebug documentation about the Command Line API.

在命令编辑器中写入monitor(functionName)，然后按 Ctrl + Enter .我什么也看不见...可能是我对该命令的理解是完全错误的.

Wrote monitor(functionName) in the command editor and pressed Ctrl+Enter. I can't see anything happening... May be my understanding of this command is completely wrong.

我用谷歌搜索，但仍然对如何使用此API命令感到困惑?

I googled but I am still confused how to use this API command?

推荐答案

对我来说很好...

查看我在 http://fiddle.jshell.net/gaby/上所做的示例LbCYn/show/

打开控制台，然后放入monitor(toBeMonitored);.现在，每次单击该按钮，它将在控制台中显示该方法已执行..

Open the console and put monitor(toBeMonitored);. Now each time you click the button it will put in the console that the method was executed..

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