计算两个函数的重叠面积 [英] Calculate overlap area of two functions
问题描述
我需要计算两个功能重叠的区域.在此特定的简化示例中,我使用正态分布,但是我还需要一个更通用的过程来适应其他功能.
I need to calculate the area where two functions overlap. I use normal distributions in this particular simplified example, but I need a more general procedure that adapts to other functions too.
请参见下图,以了解我的意思,红色区域是我想要的位置:
See image below to get an idea of what I mean, where the red area is what I'm after:
这是我到目前为止拥有的MWE:
This is the MWE I have so far:
import matplotlib.pyplot as plt
import numpy as np
from scipy import stats
# Generate random data uniformly distributed.
a = np.random.normal(1., 0.1, 1000)
b = np.random.normal(1., 0.1, 1000)
# Obtain KDE estimates foe each set of data.
xmin, xmax = -1., 2.
x_pts = np.mgrid[xmin:xmax:1000j]
# Kernels.
ker_a = stats.gaussian_kde(a)
ker_b = stats.gaussian_kde(b)
# KDEs for plotting.
kde_a = np.reshape(ker_a(x_pts).T, x_pts.shape)
kde_b = np.reshape(ker_b(x_pts).T, x_pts.shape)
# Random sample from a KDE distribution.
sample = ker_a.resample(size=1000)
# Compute the points below which to integrate.
iso = ker_b(sample)
# Filter the sample.
insample = ker_a(sample) < iso
# As per Monte Carlo, the integral is equivalent to the
# probability of drawing a point that gets through the
# filter.
integral = insample.sum() / float(insample.shape[0])
print integral
plt.xlim(0.4,1.9)
plt.plot(x_pts, kde_a)
plt.plot(x_pts, kde_b)
plt.show()
在其中应用Monte Carlo
以获得积分.
where I apply Monte Carlo
to obtain the integral.
此方法的问题在于,当我使用ker_b(sample)
(或ker_a(sample)
)评估任一分布中的采样点时,我会直接将值放置在KDE线上.因此,即使是明显重叠的分布,也应该返回非常接近1的公共/重叠区域值.而是返回较小的值(两条曲线的总面积均为1,因为它们是概率密度估计值).
The problem with this method is that when I evaluate sampled points in either distribution with ker_b(sample)
(or ker_a(sample)
), I get values placed directly over the KDE line. Because of this, even clearly overlapped distributions which should return a common/overlapped area value very close to 1. return instead small values (the total area of either curve is 1. since they are probability density estimates).
如何解决此代码以提供预期的结果?
How could I fix this code to give the expected results?
这就是我运用珍雅答案的方式
This is how I applied Zhenya's answer
# Calculate overlap between the two KDEs.
def y_pts(pt):
y_pt = min(ker_a(pt), ker_b(pt))
return y_pt
# Store overlap value.
overlap = quad(y_pts, -1., 2.)
推荐答案
图中的红色区域是min(f(x), g(x))
的整数,其中f
和g
是您的两个函数,绿色和蓝色.要评估积分,您可以使用scipy.integrate
(我会说quad
是默认值)中的任何积分器-当然也可以使用MC积分器,但是我不太明白这一点其中.
The red area on the plot is the integral of min(f(x), g(x))
, where f
and g
are your two functions, green and blue. To evaluate the integral, you can use any of the integrators from scipy.integrate
(quad
's the default one, I'd say) -- or an MC integrator, of course, but I don't quite see the point of that.
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