并行处理的最佳种子 [英] Best seed for parallel process

问题描述

我需要在不同的机器上并行运行MonteCarlo仿真.该代码是用c ++编写的，但是该程序是使用python脚本设置和启动的，该脚本设置了很多东西，尤其是随机种子. setseed函数可以获取4个字节的无符号整数

I need to run a MonteCarlo simulations in parallel on different machines. The code is in c++, but the program is set up and launched with a python script that set a lot of things, in particular the random seed. The function setseed thake a 4 bytes unsigned integer

使用简单

import time
setseed(int(time.time()))

不太好，因为我将作业提交到集群中的队列中，它们保持待命状态几分钟，然后开始运行，但是启动时间是难以置信的，可能是两个作业同时启动(秒) ，所以我切换到:

is not very good because I submit the jobs to a queue on a cluster, they remain pending for some minutes then they starts, but the start time is impredicible, it can be that two jobs start at the same time (seconds), so I switch to:

setseet(int(time.time()*100))

但是我不高兴.最好的解决方案是什么?也许我可以结合以下信息:时间，机器ID，进程ID.还是最好的解决方案是从/dev/random(Linux机器)中读取?

but I'm not happy. What is the best solution? Maybe I can combine information from: time, machine id, process id. Or maybe the best solution is to read from /dev/random (linux machines)?

如何从/dev/random中读取4个字节?

How to read 4 bytes from /dev/random?

f = open("/dev/random","rb")
f.read(4)

给我一​​个字符串，我想要一个整数！

give me a string, I want an integer!

推荐答案

从/dev/random读取是一个好主意.只需将4个字节的字符串转换为整数:

Reading from /dev/random is a good idea. Just convert the 4 byte string into an Integer:

f = open("/dev/random","rb")
rnd_str = f.read(4)

使用struct:

import struct
rand_int = struct.unpack('I', rnd_string)[0]

更新需要大写字母I.

或相乘并加:

rand_int = 0
for c in rnd_str:
    rand_int <<= 8
    rand_int += ord(c)

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