8086组件右键单击中断 [英] 8086 assembly right mouse click interrupts

问题描述

我正在Windows机器上的8086汇编中的一个项目上工作，我需要知道单击了哪个鼠标按钮.什么是中断?或如何找到答案?

I am working on a project in 8086 assembly on windows machine and I need to know which mouse button has been clicked. What are the interrupts for this? or how do I go about finding this out?

谢谢

推荐答案

如果要制作在Windows下运行的DOS程序，则可以使用软件中断0x33，函数3，该函数返回BL寄存器中的按钮状态:

If you're making a DOS program that runs under windows, you can use software interrupt 0x33, function 3, which returns the button status in the BL register :

    mov   ax,0x3
    int   0x33
    test  bl,1
    jnz   left_button_pressed
    test  bl,2
    jnz   right_button_pressed

此处有更多信息 http://www.ctyme.com/intr/rb- 5959.htm

如果您正在制作本机Windows应用程序，则可以通过检查传递到注册WndProc的标准鼠标按钮消息(WM_LBUTTONDOWN/UP，WM_RBUTTONDOWN/UP，WM_MBUTTONDOWN/UP)来测试按钮是否按下，以创建主窗口通过您的程序.

If you're making a native Windows application, you can test for button presses by checking for the standard mouse button messages (WM_LBUTTONDOWN/UP , WM_RBUTTONDOWN/UP , WM_MBUTTONDOWN/UP) passed to your registered WndProc for the main window created by your program.

WndProc的函数声明为"LRESULT CALLBACK WindowProc(HWND hwnd，UINT uMsg，WPARAM wParam，LPARAM lParam);"，消息类型以uMsg传递，因此您需要在[esp + 12中检查DWORD ]，然后将其与您要处理的消息ID进行比较.

The function declaration for the WndProc is "LRESULT CALLBACK WindowProc(HWND hwnd, UINT uMsg, WPARAM wParam, LPARAM lParam);", the message type is passed in uMsg, so you'd check the DWORD at [esp+12] and compare it with the message ID you want to handle.

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