通过发送消息单击鼠标 [英] Clicking mouse by sending messages
问题描述
我正在尝试将鼠标点击发送给程序.因为我不希望鼠标移动,所以我不想使用SendInput或mouse_event,并且由于应该接收点击的窗口并没有真正使用Buttons或其他GUI事件,所以我无法向这些消息发送消息按钮.
I'm trying to send mouse clicks to a program. As I don't want the mouse to move, I don't want to use SendInput or mouse_event, and because the window that should receive the clicks doesn't really use Buttons or other GUI events, I can't send messages to these buttons.
我正在尝试使用SendMessage使其正常工作,但是由于某些原因,它不起作用.相关代码是(在C#中,但也在jnative上尝试过Java),在Vista上尝试过
I'm trying to get this working using SendMessage, but for some reason it doesn't work. Relevant code is (in C#, but tried Java with jnative as well), trying this on Vista
[DllImport("user32.dll", CharSet=CharSet.Auto)]
public static extern int SendMessage(IntPtr A_0, int A_1, int A_2, int A_3);
static int WM_CLOSE = 0x10;
static int WM_LBUTTONDOWN = 0x201;
static int WM_LBUTTONUP = 0x202;
public static void click(IntPtr hWnd, int x, int y)
{
SendMessage(hWnd, WM_LBUTTONDOWN, 1, ((x << 0x10) ^ y));
SendMessage(hWnd, WM_LBUTTONUP, 0, ((x << 0x10) ^ y));
}
public static void close(IntPtr hWnd)
{
SendMessage(hWnd, WM_CLOSE, 0, 0);
}
close
可以正常工作,但是click
却什么也没做.
The close
works fine, but the click
doesn't do anything.
发现了问题.除了如下所述的替换x和y坐标的愚蠢错误外,我没有检查接收点击的Window句柄是否也是正确的客户端窗口.我现在有
edit: Found the problem. Besides the stupid bug to replace the x and y coordinates, as suggested below, I didn't check if the Window handle that receives the click is also the correct client window. I now have
POINT p = new POINT(x, y);
IntPtr hWnd = WindowFromPoint(p);
RECT rct = new RECT();
if (!GetWindowRect(hWnd, ref rct))
{
return;
}
int newx = x - rct.Left;
int newy = y - rct.Top;
SendMessage(hWnd, WM_LBUTTONDOWN, 1, newy * 65536 + newx);
SendMessage(hWnd, WM_LBUTTONUP, 0, newy * 65536 + newx);
效果很好.
推荐答案
问题在于您打包x,y坐标.
The problem is with your packing of the x,y coordinates.
-
y
应该是高阶词 - 您应该使用| (按位或)以组合坐标对的组成部分
y
should be in the high order word- You should use | (bitwise or) to combine the components of the coordinate pair
您应该具备以下条件
((y << 0x10) | x)
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