mouseEntered将不会执行 [英] mouseEntered will not execute
本文介绍了mouseEntered将不会执行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试进行mouseEntered测试以更改正方形颜色,但是不会执行MouseListener mouseEntered.鼠标正在响应,但仅响应单击,按下并释放.所以我不确定发生了什么.希望您能帮我指出我的问题,谢谢.
I am trying to do a mouseEntered test to change a square colour however the MouseListener mouseEntered would not execute. The mouse is responding but only to clicks, pressed and release. So i am not sure what is going on. I hope you can help me point my problem thanks.
//Class
class RectangleClass extends JPanel{
private int height;
private int width;
private boolean MouseEntered= false;
private boolean MouseExit= false;
private JPanel myPanel = new JPanel();
//Inner class with mouse Event
class RectangleAdapter extends MouseAdapter{
public void MouseEntered(MouseEvent e){
System.out.println("MouseEntered");
MouseEntered = true;
repaint();
}
public void MouseExited(MouseEvent e){
System.out.println("MouseExited");
MouseExit = true;
repaint();
}
}
//constructor
public RectangleClass(int height,int width){
myPanel = this;
this.height=height;
this.width=width;
this.addMouseListener(new RectangleAdapter());
}
//paint graphic
public void paint(Graphics g){
super.paint(g);
g.clearRect(0, 0, width, height);
g.drawRect(0, 0, width, height);
g.setColor(Color.YELLOW);
if (MouseEntered){
g.setColor(Color.CYAN);
MouseEntered= false;
}
if (MouseExit){
g.setColor(Color.orange);
MouseExit= false;
}
g.fillRect(0, 0, width, height);
}
}
public class RectangleContainer extends JFrame{
public RectangleContainer(){
setLayout(null);
JPanel myPanel = new RectangleClass(100,100);
myPanel.setBounds(50, 50, 200, 200);
setSize(200,200);
add(myPanel);
setVisible(true);
}
public static void main(String args[]){
new RectangleContainer();
}
}
推荐答案
您已经在代码中以大写M开头了mouseEntered
方法.将其更改为小写m.
You have started the mouseEntered
method in your code with a capital M. Change it to lowercase m.
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