是否存在利用move优势的back_inserter变体? [英] Is there a back_inserter variant that takes advantage of move?
问题描述
在通用代码中,我试图告诉输出迭代器(实际上是std::back_inserter_iterator
来移动一系列元素.令我惊讶的是,看起来好像是在move-to-back_inserter操作中移动了元素.
In generic code I was trying to tell an output iterator (in practice a std::back_inserter_iterator
to move a range of elements. To my surprise it looked as if elements were moved in a move-to-back_inserter operation.
#include<algorithm> // move
#include<iterator> // back_inserter
#include<vector>
int main(){
std::vector<std::vector<double> > v(10, std::vector<double>(100));
std::vector<std::vector<double> > w;
assert( not v[0].empty() and w.size() == 0 );
std::copy(v.begin(), v.end(), std::back_inserter(w));
assert( not v[0].empty() and w.size() == 10 );
std::move(v.begin(), v.end(), std::back_inserter(w));
assert( v[0].empty() and w.size() == 20 ); // were v elements moved to w?
}
但是,我认为v
的元素实际上并没有移到w
的可能性,因为毕竟back_inserter
会执行push_back
,这意味着要复制到w
.
However I don't think it is possible that elements of v
were really moved to w
, because after all back_inserter
will do a push_back
which implies a copy to w
.
在std::move
情况下,很可能将v
元素移到了临时元素,然后才复制到w
.
It seems more likely that in the std::move
case, v
elements were moved to a temporary and only then copied into w
.
正确吗? std::back_inserter
是否真的以某种方式移动?
Is that correct? Is there a std::back_inserter
really moving somehow?
是否已经有std::back_inserter
的变体利用了移动/进位?类似于std::back_emplacer
的东西?
Is there already a variant of std::back_inserter
that takes advantage of move/emplace? Something like an std::back_emplacer
?
推荐答案
std::back_inserter()
是用于创建 std::back_insert_iterator
对象.
std::back_insert_iterator
类已经operator=
重载,可以使用 rvalue引用类型,即:
The class std::back_insert_iterator
has already operator=
overloaded for taking rvalue reference types, i.e.:
back_insert_iterator<Container>& operator=(typename Container::value_type&& value);
因此,std::back_insert_iterator
已经准备好利用移动语义.
Therefore, std::back_insert_iterator
is already prepared to take advantage of move semantics.
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