如何使用ffmpeg将x3的mp3裁剪为x + n? [英] How to crop a mp3 from x to x+n using ffmpeg?

问题描述

在这个问题之后，我决定使用ffmpeg裁剪MP3.在另一个问题上，我发现了这样做的方法:

Following this question I decided to use ffmpeg to crop MP3s. On another question I found this way of doing it:

ffmpeg -t 30 -acodec copy -i inputfile.mp3 outputfile.mp3

问题是我不想在前30秒内进行裁剪，而是想从x裁剪为x + n，例如从30s裁剪为100s.我怎么去做呢?

The problem is that I don't want to crop the first 30 seconds, I want to crop from x to x+n, like from 30s to 100s. How would I go and do this?

我正在阅读ffmpeg的人，但这并不是很简单，特别是由于我只是发现ffmpeg的知识，而且我对音频/视频编辑软件不熟悉，因此任何指针都将不胜感激.

I'm reading the man for ffmpeg but this is not really straightforward, especially since I just discovered about ffmpeg and I'm not familiar with audio/video editing softwares, so any pointers would be appreciated.

推荐答案

看看-t和-ss参数.他们应该做你想做的事.

Take a look at the -t and -ss arguments. They should do what you want.

-t持续时间

-t duration

限制转码/捕获的视频 顺序为中指定的持续时间 秒. hh:mm:ss [.xxx]语法也是 支持的.

Restrict the transcoded/captured video sequence to the duration specified in seconds. hh:mm:ss[.xxx] syntax is also supported.

-ss位置'

以秒为单位搜索到给定的时间位置. hh:mm:ss [.xxx]语法也受支持.

Seek to given time position in seconds. hh:mm:ss[.xxx] syntax is also supported.

例如，ffmpeg -ss 30 -t 70 -i inputfile.mp3 -acodec copy outputfile.mp3应该在您提到的范围(30s-100s)内起作用.

For example, ffmpeg -ss 30 -t 70 -i inputfile.mp3 -acodec copy outputfile.mp3 should do the trick for the range you mentioned (30s-100s).

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