如何在MS Access vba脚本中使用参数生成URL? [英] How to generate URL with parameters in MS Access vba script?

问题描述

我有一个MS Access应用程序，该应用程序在表单上具有一个按钮，该按钮应移动文件，更新记录的字段并打开具有以下参数的网页: 1)访问记录的ID； 2)更新字段的值； 3)密码.

I have a MS Access application that has a button on a form that should move files, update a field of the record and open a webpage with the following parameters: 1) the ID of the Access record 2) value of the updated field 3) secretword.

除打开网页外，其他所有功能都正常.

Everything works fine except opening webpage.

我已将此文章设为红色:如何从带有参数的MS Access中打开一个URL ，然后编写以下行:CreateObject("Shell.Application")...

I've red this article:How to open a URL from MS Access with parameters and compose the line CreateObject("Shell.Application")...

            FSO.MoveFolder FLD_READY & "\" & rs.Fields(order_int_ID), FLD_SERVER & "\" & rs.Fields(order_int_ID)
            rs.Edit: rs.Fields(order_stage) = os07: rs.Update
            CountFile = CountFile + 1
            CreateObject("Shell.Application").Open "https://example.com/status/" & "/" & rs.Fields(order_int_ID) & "/" & 'os07' & "/" & 'secretword' 

请问-这是怎么了?我应该如何对其进行更改才能使其正常工作?

Could you please tell - what is wrong with it? How should I change it to get it working?

这是整个脚本.提到的代码块几乎在它的结尾.

Here is the whole script. The mentioned block is almost in the end of it.

' Order_stage status
Private Const os06 = "06"
Private Const os07 = "07"

' Transfer to server
Private Const FTP_TRANSFER_TYPE_UNKNOWN     As Long = 0
Private Const INTERNET_FLAG_RELOAD          As Long = &H80000000
Private Const FORMAT_MESSAGE_FROM_HMODULE = &H800
Private szErrorMessage As String
Private Const INTERNET_OPEN_TYPE_PRECONFIG = 0
Private Const FTP_TRANSFER_TYPE_ASCII = &H1
Private dwType As Long
Private Const FtpConnectionFile = "D:\ftp_connection.txt"
Private Const FTP_UP_HOME = "public_html/"


'Folders
Private Const FLD_READY = "d:\10-5-0-Ready"
Private Const FLD_SERVER = "d:\10-6-0-Server"



Private Sub Ctl10_50___SERVER_Click()

  Dim ftpHost As String
  Dim ftpPort As Long
  Dim ftpUser As String
  Dim ftpPassword As String

  Dim CountFile As Integer
  Dim hOpen   As Long
  Dim hConn   As Long
  Dim hPut    As Long

  Dim ftpCurrentDirectory As String
  Dim szDir As String

  Dim strTextLine As String
  Dim FSO As Object
  Set FSO = CreateObject("Scripting.FileSystemObject")

  Dim oFolder As Object
  Dim oSubFolder As Object
  Dim oFile As Object
  Dim strFileExt As String
  Dim Strt As Integer

  Dim i As Integer: i = 0

  Dim iFile As Integer: iFile = FreeFile
  Open FtpConnectionFile For Input As #iFile
  Do Until EOF(1)
    Line Input #1, strTextLine
    Select Case i
     Case Is = 0:               ftpHost = Trim(strTextLine)
     Case Is = 1:               ftpPort = CLng(Trim(strTextLine))
     Case Is = 2:               ftpUser = Trim(strTextLine)
     Case Is = 3:               ftpPassword = Trim(strTextLine)
     Case Is = 4:               Exit Do
    End Select
    i = i + 1
  Loop
  Close #iFile

  hOpen = InternetOpenA("FTP Client", INTERNET_OPEN_TYPE_PRECONFIG, vbNullString, vbNullString, 0)
  If hOpen = 0 Then
        ErrorOut Err.LastDllError, "InternetOpen"
  End If

  dwType = FTP_TRANSFER_TYPE_ASCII

  hConn = InternetConnectA(hOpen, ftpHost, ftpPort, ftpUser, ftpPassword, 1, 0, 0)
  If hConn = 0 Then
        ErrorOut Err.LastDllError, "InternetConnect"
  End If

  If (FtpCreateDirectory(hConn, FTP_UP_HOME) = False) Then
        ErrorOut Err.LastDllError, "FtpCreateDirectory"
  Else
  End If

  If (FtpSetCurrentDirectory(hConn, FTP_UP_HOME) = False) Then
        ErrorOut Err.LastDllError, "FtpCreateDirectory"
  Else
  End If

   For Each oFolder In FSO.GetFolder(FLD_CHECK).SubFolders
     For Each oFile In oFolder.Files

        strFileExt = FSO.GetExtensionName(oFile)
       'MsgBox (strFileExt)
       If strFileExt = "psd2" Then
         Dim rs2 As Recordset
         Set rs2 = CurrentDb.OpenRecordset("SELECT A_INCOMING_ORDERS.order_int_ID, A_INCOMING_ORDERS.order_stage FROM A_INCOMING_ORDERS WHERE (A_INCOMING_ORDERS.order_int_ID = '" & oFolder.Name & "')")

         Do While Not rs2.EOF
            rs2.Edit: rs2.Fields(order_stage) = os40: rs2.Update
         rs2.MoveNext
         Loop
         rs2.Close
          FSO.MoveFolder oFolder.Path, FLD_ALTER & "\" & oFolder.Name

        End If

      Next
Next

  Dim rs As Recordset
  Set rs = CurrentDb.OpenRecordset("SELECT A_INCOMING_ORDERS.order_int_ID, A_INCOMING_ORDERS.order_stage FROM A_INCOMING_ORDERS WHERE (A_INCOMING_ORDERS.order_stage = '" & os06 & "');")
  CountFile = 0
  Do While Not rs.EOF

     If (FSO.FolderExists(FLD_READY & "/" & rs.Fields(order_int_ID))) Then
            If (FtpCreateDirectory(hConn, rs.Fields(order_int_ID)) = False) Then
               ErrorOut Err.LastDllError, "FtpCreateDirectory"
            Else
            End If

            For Each oFile In FSO.GetFolder(FLD_READY & "/" & rs.Fields(order_int_ID)).Files
               hPut = FtpPutFileA(hConn, FLD_READY & "/" & rs.Fields(order_int_ID) & "/" & oFile.Name, "/" & FTP_UP_HOME & "/" & rs.Fields(order_int_ID) & "/" & oFile.Name, 2, 0)
               If hPut = 0 Then
                  ErrorOut Err.LastDllError, "FtpPutFileA"
               Else
               End If
            Next
            FSO.MoveFolder FLD_READY & "\" & rs.Fields(order_int_ID), FLD_SERVER & "\" & rs.Fields(order_int_ID)
            rs.Edit: rs.Fields(order_stage) = os07: rs.Update
            CountFile = CountFile + 1
     CreateObject("Shell.Application").Open "https://example.com/status/" & "/" & rs.Fields(order_int_ID) & "/" & 'os07' & "/" & 'secretword'

     End If


  rs.MoveNext
  Loop
  rs.Close

  InternetCloseHandle hConn
  InternetCloseHandle hOpen
  MsgBox "Count: " & CountFile
End Sub

推荐答案

此问题的答案是:

Application.FollowHyperlink "https://example.com/status/" & rs.Fields(order_int_ID) & "/" & "os07" & "/" & "secretword", , True

此解决方案适用于我.

This solution works for me.

这篇关于如何在MS Access vba脚本中使用参数生成URL?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！