调用从Android应用程序的Web服务 [英] calling a web service from an android application
问题描述
我用下面的code,我互联网上找到调用从我的Android应用程序的Web服务:
I am using the following code which i found on internet to call a web service from my android app:
public class WebServiceActivity extends Activity {
private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
private static final String METHOD_NAME = "HelloWorld";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button getquote = (Button) findViewById(R.id.getquote);
getquote.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
TextView result1;
result1=(TextView)findViewById(R.id.result1);
try {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
EditText CompanyName = (EditText) findViewById(R.id.CompanyName);
String val1 = (CompanyName.getText().toString());
request.addProperty("passonString", val1);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet=true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
Object result = (Object)envelope.getResponse();
result1.setText(result.toString());
} catch (Exception e) {
result1.setText(e.getMessage());
}
}
});
}
}
我收到错误的应用不是responding.I是外地的新的,请大家帮忙。
在此先感谢
I am getting error that application is not responding.I am new in the field , please help. Thanks in advance
推荐答案
把你的Web服务请求作为后台任务。通常是由网络活动所用的时间是联合国predictable。如果你使用上面,UI线程将阻塞。这就是为什么它说:应用程序没有响应。
Put your web service request as a background task. Usually time taken by a network activity is unpredictable. If you use above, the UI Thread will block. That is why it says "Application not responding".
我发现这篇大文章。
http://www.vogella.de/articles/AndroidPerformance/article.html#concurrency
看看2.后台处理
I found this great article. http://www.vogella.de/articles/AndroidPerformance/article.html#concurrency Have a look at 2. Background Processing
您的例子可以修改如下。
Your example can be modified as following.
public class WebServiceActivity extends Activity {
private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
private static final String METHOD_NAME = "HelloWorld";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx";
TextView result1;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
result1 = (TextView) findViewById(R.id.result1);
Button getquote = (Button) findViewById(R.id.getquote);
getquote.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// push soap request into background.
new Thread(new Runnable(){
@Override
public void run() {
doSoapRequest();
}
},"DOINBACKGROUND");
}
});
}
private void doSoapRequest(){
try {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
EditText CompanyName = (EditText) findViewById(R.id.CompanyName);
String val1 = (CompanyName.getText().toString());
request.addProperty("passonString", val1);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(
URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
Object result = (Object) envelope.getResponse();
// result1.setText(result.toString());
// update UI data in a Handler
Message msg = new Message();
msg.obj = result.toString();
result1Handler.sendMessage(msg);
} catch (Exception e) {
// result1.setText(e.getMessage());
// update UI data in a Handler
Message msg = new Message();
msg.obj = e.getMessage();
result1Handler.sendMessage(msg);
}
}
private Handler result1Handler = new Handler(){
@Override
public void handleMessage(Message msg) {
super.handleMessage(msg);
result1.setText(msg.obj.toString());
}
};
}
这篇关于调用从Android应用程序的Web服务的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!