MSBuild条件IsDebug [英] MSBuild Condition IsDebug

问题描述

如何确定项目是否在MSBuild .targets文件中以调试(或发布)模式构建，并将此信息用作其他属性的条件?

How can I determine if a project is build in Debug (or Release) mode within an MSBuild .targets file and use this information as a condition for another property?

类似的东西:

<OutDir Condition="IsDebug">bin\Debug\$(SomeOtherProperty)\</OutDir>
<OutDir Condition="!IsDebug">bin\Release\$(SomeOtherProperty)\</OutDir>

是否存在诸如调试/发布"模式之类的东西，还是只是针对不同配置属性值集的常规名称?

Is there such thing as Debug/Release mode, or are they just conventional names for different sets of configuration properties' values?

推荐答案

调试/发布或Configuration属性的常规值.

Debug/Release or whatever are just conventional values for the Configuration property.

因此，只要包含/调用您的.targets文件的项目遵守约定；您可以按以下方式检查调试模式:

So, as long the project that includes/calls your .targets file adheres to the convention; you can check for debug mode as follows:

<OutDir>bin\Release\$(SomeOtherProperty)\</OutDir>
<OutDir Condition=" '$(Configuration)' == 'Debug' ">bin\Debug\$(SomeOtherProperty)\</OutDir>

或者您可以直接使用该变量:

or you could just use that variable directly:

<OutDir>bin\$(Configuration)\$(SomeOtherProperty)\</OutDir>

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