msbuild从属性组创建项目组 [英] msbuild create itemgroup from property group

问题描述

我想传递用分号分隔的字符串列表.
每个字符串代表一个文件名.

I want to pass a semi-colon separated list of strings.
Each string represents a file name.

    <PropertyGroup>
          <FileNames>Newtonsoft.Json;Reactive</FileNames>
          <PathToOutput>C:/</PathToOutput>
    </PropertyGroup>

现在，我想创建一个项目组，该组应该给我所有特定文件夹中的文件，但不包括文件名列表，例如:

Now I want to create an item group which should give me all the files in particular folder excluding list of Filename, something like:

<ItemGroup>
    <ReleaseFiles Include="$(PathToOutput)\**\*.*" Exclude="%(identity)-> identity.contains(%FileNames)"/>
</ItemGroup>

如果文件名变量中包含任意一个文件名，如何遍历当前文件夹的文件并匹配每个文件名.

How do I iterate through current folder's files and match each ones name if it contains any one filename in Filenames variable.

推荐答案

很确定这是一个重复项，但是我暂时找不到，所以在这里:

Pretty sure this is a duplicate but I cannot find it at the moment so here it goes:

• 将分号分隔的属性转换为项目只是使用Include=$(Property)
• Exclude仅在具有完全匹配列表的情况下有效，但是您需要在此处进行更多任意过滤，因此您需要Condition
通过使ReleaseFiles项目的那些FileNames元数据，像交叉产品一样将两个ItemGroups连接在一起.然后，您可以遍历Rel​​easeFiles中的每个项目并同时访问FileNames
• Contains是属性函数(或者是System :: String方法)，因此无法在元数据上使用，因此我们首先将元数据转换为字符串

• turning a semicolon-seperated property into an item is just a matter of using Include=$(Property)
• Exclude only works if you have a list of exact matches, but you need more arbitrary filtering here so you'll need Condition
• join the two ItemGroups together like a cross-product, by making those FileNames metadata of the ReleaseFiles item. Then you can iterate over each item in ReleaseFiles and have access to the FileNames at the same time
• Contains is a property function (well, or a System::String method) so won't work as such on metadata, hence we turn metadata into a string first

在代码中:

<PropertyGroup>
  <FileNames>Newtonsoft.Json;Reactive</FileNames>
  <PathToOutput>C:/</PathToOutput>
</PropertyGroup>

<Target Name="FilterBasedCommaSeperatedProperty">
  <ItemGroup>
    <!-- property -> item -->
    <Excl Include="$(FileNames)"/>
    <!-- list all and add metadata list -->
    <AllReleaseFiles Include="$(PathToOutput)\**\*.*">
      <Excl>%(Excl.Identity)</Excl>
    </AllReleaseFiles >
    <!-- filter to get list of files we don't want -->
    <FilesToExclude Include="@(AllReleaseFiles)"
                    Condition="$([System.String]::Copy('%(FileName)').Contains('%(Excl)'))"/>
    <!-- all but the ones to exclude --> 
    <ReleaseFiles Include="@(AllReleaseFiles)" Exclude="@(FilesToExclude)"/>
  </ItemGroup>
  <Message Text="%(ReleaseFiles.Identity)" />
</Target>

这篇关于msbuild从属性组创建项目组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！