从MsBuild定义C#预处理程序 [英] Define C# preprocessor from MsBuild

问题描述

在我的C#文件中，我希望具有这样的预处理条件:

In my C# file I want to have a preprocessor condition like this:

#if DEMO
    ShowSplash();
#endif

我正在从命令行运行此命令:

I'm running this command from command line:

MSBuild MySolution.sln /p:Configuration=Release /p:Platform="Any CPU" /p:DEMO=1

然后，在MyProject.csproj文件中，我具有以下内容:

Then, in MyProject.csproj file I have the following:

<PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Release|AnyCPU' ">
    <DefineConstants>TRACE;DEMO=$(DEMO)</DefineConstants>
</PropertyGroup>

但是预处理器似乎跳过了我的启动代码. (我知道"Any CPU"和"AnyCPU"之间的区别.我从没碰过它，所以我很确定Visual Studio不在乎空间.)

But the preprocessor seems to skip my splash code. (I'm aware of the difference between "Any CPU" and "AnyCPU". I never touched that, so I'm quite sure Visual Studio doesn't care about the space.)

DEMO未定义?相同的构造似乎可以在其他项目类型中使用(例如.wixproj)我在这里缺少什么?

DEMO is not defined? The same construct seems to work in other project types (e.g. .wixproj) What am I missing here?

推荐答案

首先，您应该只在以下位置定义(并在您的代码中进行测试)符号:DEMO

First, you should only define (and test in your code) the symbol, here: DEMO

然后，您应该有条件地将符号添加到现有符号(最终在项目属性中定义的符号):

Then, you should conditionally add your symbol to existing symbols (those eventualy defined in project's properties):

在.csproj文件中的第一项<DefineConstants>或创建另一个<PropertyGroup>部分之后，添加以下行: <DefineConstants Condition="'$(DEMO)'=='1'">$(DefineConstants);DEMO</DefineConstants>

In .csproj file, after first item <DefineConstants> or creating another <PropertyGroup> section, add line: <DefineConstants Condition="'$(DEMO)'=='1'">$(DefineConstants);DEMO</DefineConstants>

PS:这是一个经过测试的解决方案.

PS: this is a tested solution.

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