如何在Python中初始化二维数组? [英] How to initialize a two-dimensional array in Python?

问题描述

我开始使用python，并尝试使用一个二维列表，最初我在每个地方都填充了相同的变量.我想到了这个:

I'm beginning python and I'm trying to use a two-dimensional list, that I initially fill up with the same variable in every place. I came up with this:

def initialize_twodlist(foo):
    twod_list = []
    new = []
    for i in range (0, 10):
        for j in range (0, 10):
            new.append(foo)
        twod_list.append(new)
        new = []

它给出了预期的结果，但是感觉像是一种解决方法.有没有更简单/更短/更优雅的方式来做到这一点?

It gives the desired result, but feels like a workaround. Is there an easier/shorter/more elegant way to do this?

推荐答案

Python中经常出现的一种模式是

A pattern that often came up in Python was

bar = []
for item in some_iterable:
    bar.append(SOME EXPRESSION)

这有助于激励列表理解的引入，从而将代码段转换为

which helped motivate the introduction of list comprehensions, which convert that snippet to

bar = [SOME EXPRESSION for item in some_iterable]

更短，有时更清晰.通常您会养成识别这些习惯的习惯，并经常用理解代替循环.

which is shorter and sometimes clearer. Usually you get in the habit of recognizing these and often replacing loops with comprehensions.

您的代码两次遵循此模式

Your code follows this pattern twice

twod_list = []                                       \                      
for i in range (0, 10):                               \
    new = []                  \ can be replaced        } this too
    for j in range (0, 10):    } with a list          /
        new.append(foo)       / comprehension        /
    twod_list.append(new)                           /

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