在PHP中比较一维数组和多维数组的快速方法 [英] Fastes way to compare single-dimensional against multidimensional array in PHP

问题描述

我有一个像这样的多维数组:

I have a multidimensional array like this:

Array (
[0] => Array
    (
        [time] => 1364685993
        [memberid] => 131
    )

[1] => Array
    (
        [time] => 1364685994
        [memberid] => 133
    )
[2] => Array
    (
        [time] => 1364685995
        [memberid] => 141
    )
)

和像这样的一维数组:

Array (
  [0] => 131
  [1] => 141
  [2] => 191
  [3] => 205
)

现在我要从不包含普通数组中的memberid值的多维数组中删除所有子数组?

Now I want to remove all Sub-arrays from multidimensional arrays that DOES NOT contain the memberid value from normal array ?

在这种情况下，只有Subaray [1]要从多维数组中删除，因为它的"memberid"键值(133)在正常数组中不显示.这些数组实际上很大，所以我不确定最快的方法是什么?

In this case only Subaray[1] to be removed from multidimensional array as it's 'memberid' key value (133) doesn't show in normal array. Those arrays are actually pretty big, so I am not sure what would be fastest way to do it ?

推荐答案

首先，我将翻转$nomal数组，以便在数组中获得恒定的查找时间，如下所示:

First, I would flip the $nomal array to get constant lookup time into the array, like this:

$normal = array_flip( $normal);

然后，您只需要通过简单的查找就可以通过$normal数组过滤$multidimensional_array:

Then, you just have to filter the $multidimensional_array by the $normal array with a simple lookup:

$filtered = array_filter( $multidimensional_array, function( $el) use( $normal) {
    return isset( $normal[ $el['member_id'] ]);
});

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