比较项目并将其添加到对象数组 [英] comparing and adding items to array of objects

问题描述

下面的代码应该:

1)遍历两个数组，

2)如果两个数组中都存在一项，则将其值添加到第一个数组中类似项的值，

2) if an item exist in both arrays, add its value to the value of the similar item in the first array,

3)如果在arr2中找到了该项目，但在arr1中找不到，则将该项目添加到arr1中.当两个数组的大小相同时，我的代码可以正常工作，但这是我使用不同大小的数组得到的.

3) if the item is found in arr2 but not arr1, add the item to arr1. My code works as desired when both arrays have the same size, but this is what I get with arrays of different size.

结果:

[[42，保龄球"]，[4，脏袜子"]，[2，猫"]，[6，杯子"]，[2， 脏袜子"]，[3，破布"]]

[[42, "Bowling Ball"], [4, "Dirty Sock"], [2, "cat"], [6, "mugs"], [2, "Dirty Sock"], [3, "rags"]]

应为:

[[42，保龄球"]，[4，脏袜子"]，[2，猫"]，[3，抹布"]，[3， 杯子"]]

[[42, "Bowling Ball"], [4, "Dirty Sock"], [2, "cat"], [3, "rags"], [3, "mugs"]]

这是我的代码:

function updateInventory(arr1, arr2) {
  for (var i = 0; i < arr1.length; i++) {
    for (var j = i; j < arr2.length; j++) {
      if (arr1[i][1] === arr2[j][1]) {
        arr1[i][0] += arr2[j][0];
      }
      if (arr1[i].indexOf(arr2[j][1]) === -1) {
        arr1.push(arr2[j]);
      }
      if (arr2.length > arr1.length) {
        arr1.push(arr2[arr2.length -1]);
      }
      else
        break;
    }
  }
  return arr1;
}

var curInv = [
    [21, "Bowling Ball"],
    [2, "Dirty Sock"],
    [2, "cat"],
];

var newInv = [
    [21, "Bowling Ball"],
    [2, "Dirty Sock"],
    [3, "rags"],
    [3, "mugs"]
];

updateInventory(curInv, newInv);

这是什么问题?

推荐答案

您可以使用哈希表作为清单，并检查并更新currInv.

You could use a hash table for the inventory and check against and update currInv.

var curInv = [[21, "Bowling Ball"], [2, "Dirty Sock"], [2, "cat"], ],
    newInv = [[21, "Bowling Ball"], [2, "Dirty Sock"], [3, "rags"], [3, "mugs"]],
    inventory = Object.create(null);

curInv.forEach(function (a) {
    this[a[1]] = a;
}, inventory);

newInv.forEach(function (a) {
    if (!this[a[1]]) {
        this[a[1]] = [0, a[1]];
        curInv.push(this[a[1]]);
    }
    this[a[1]][0] += a[0];
}, inventory);

console.log(curInv);

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