在Ruby中对正则表达式进行分组 [英] Grouping Regex in Ruby

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本文介绍了在Ruby中对正则表达式进行分组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

示例文字

    outline: 4 0
      corner: 1 347980000 -2540000 0
      corner: 2 347980000 -20320000 0
      corner: 3 482600000 -20320000 0
      corner: 4 482600000 -2540000 0

    outline: 4 1
      corner: 1 0 -2540000 0
      corner: 2 345440000 -2540000 0
      corner: 3 345440000 -20320000 0
      corner: 4 0 -20320000 0

    outline: 8 2
      corner: 1 0 0 0
      corner: 2 0 35560000 0
      corner: 3 53340000 35560000 0
      corner: 4 53340000 76200000 0
      corner: 5 449580000 76200000 0
      corner: 6 449580000 30226000 0
      corner: 7 482600000 30226000 0
      corner: 8 482600000 0 0

    outline: 4 3
      corner: 1 0 38100000 0
      corner: 2 50800000 38100000 0
      corner: 3 50800000 76200000 0
      corner: 4 0 76200000 0

    outline: 4 4
      corner: 1 482600000 76200000 0
      corner: 2 482854000 31750000 0
      corner: 3 450850000 31750000 0
      corner: 4 450850000 76200000 0

/^\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)/m 捕获拐角的所有值.

/^\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)/m Captures all values for corners.

/^\s*outline:\s*(\d+)\s+(\d+)$.*?\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)/m 捕获所有轮廓,但仅捕获每个轮廓的第一个角.

/^\s*outline:\s*(\d+)\s+(\d+)$.*?\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)/m Captures all outlines, but only the first corner of each outline.

/^\s*outline:\s*(\d+)\s+(\d+)$.*?(^\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)$).*?/m 与第二个功能相同,但是看起来像这样:

/^\s*outline:\s*(\d+)\s+(\d+)$.*?(^\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)$).*?/m Does the same thing as the second, but looks like this:

4
0
corner: 1 347980000 -2540000 0
1
347980000
-2540000
0

我正在尝试获取所有轮廓和相关角点.显然没有正确分组-有任何建议吗?

I am trying to get it to capture all of the outlines and related corners. It's obviously not properly grouped - Any suggestions?

谢谢;-)

推荐答案

由于所需的捕获数量有所不同(可能没有限制),因此您无法在一个正则表达式中执行此操作.在这种情况下String#scan会派上用场.

Since the number of captures you want varies (probably without limit), you cannot do that in one regex. String#scan comes in handy in such case.

text.scan(/^\s*outline:\s*(\d+)\s+(\d+)\n(.*?)(?:\n\n|\z)/m)
.map{|a, b, corners| [a, b, corners.scan(/^\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)/)]}

会给您:

[["4", "0",
  [["1", "347980000", "-2540000", "0"],
   ["2", "347980000", "-20320000", "0"],
   ["3", "482600000", "-20320000", "0"],
   ["4", "482600000", "-2540000", "0"]]],
 ["4", "1",
  [["1", "0", "-2540000", "0"],
   ["2", "345440000", "-2540000", "0"],
   ["3", "345440000", "-20320000", "0"],
   ["4", "0", "-20320000", "0"]]],
 ["8", "2",
  [["1", "0", "0", "0"],
   ["2", "0", "35560000", "0"],
   ["3", "53340000", "35560000", "0"],
   ["4", "53340000", "76200000", "0"],
   ["5", "449580000", "76200000", "0"],
   ["6", "449580000", "30226000", "0"],
   ["7", "482600000", "30226000", "0"],
   ["8", "482600000", "0", "0"]]],
 ["4", "3",
  [["1", "0", "38100000", "0"],
   ["2", "50800000", "38100000", "0"],
   ["3", "50800000", "76200000", "0"],
   ["4", "0", "76200000", "0"]]],
["4", "4",
  [["1", "482600000", "76200000", "0"],
   ["2", "482854000", "31750000", "0"],
   ["3", "450850000", "31750000", "0"],
   ["4", "450850000", "76200000", "0"]]]]

如果要数字而不是字符串,

If you want numbers instead of strings,

text.scan(/^\s*outline:\s*(\d+)\s+(\d+)\n(.*?)(?:\n\n|\z)/m)
.map{|a, b, corners| [a.to_i, b.to_i, corners.scan(/^\s+corner:\s*(\d+)\s+(-?\d+)\s+(-?\d+)\s+(\d+)/).map{|a| a.map(&:to_i)}]}

会给您:

[[4, 0,
  [[1, 347980000, -2540000, 0],
   [2, 347980000, -20320000, 0],
   [3, 482600000, -20320000, 0],
   [4, 482600000, -2540000, 0]]],
 [4, 1,
  [[1, 0, -2540000, 0],
   [2, 345440000, -2540000, 0],
   [3, 345440000, -20320000, 0],
   [4, 0, -20320000, 0]]],
 [8, 2,
  [[1, 0, 0, 0],
   [2, 0, 35560000, 0],
   [3, 53340000, 35560000, 0],
   [4, 53340000, 76200000, 0],
   [5, 449580000, 76200000, 0],
   [6, 449580000, 30226000, 0],
   [7, 482600000, 30226000, 0],
   [8, 482600000, 0, 0]]],
 [4, 3,
  [[1, 0, 38100000, 0],
   [2, 50800000, 38100000, 0],
   [3, 50800000, 76200000, 0],
   [4, 0, 76200000, 0]]],
[4, 4,
  [[1, 482600000, 76200000, 0],
   [2, 482854000, 31750000, 0],
   [3, 450850000, 31750000, 0],
   [4, 450850000, 76200000, 0]]]]

这篇关于在Ruby中对正则表达式进行分组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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