什么是更好的方法来从字符串修剪不可打印的字符 [英] What is the better approach to trim unprintable characters from a string

问题描述

我从XML读取数据。当我在eclipse控制台检查，我发现我得到了一些方盒子整个数据。 示例如果没有在excel表我得到123与一些方盒子123。我用修剪（）来避免这样的事情，但因此未获得成功，因为TRIM（）方法只修剪空格。但我发现这些字符有ASCII值-17，-20 .. 我不想只修剪空格我要修剪那些方盒子也

所以我用下面的方法来削减这些字符，我得到了成功。

这是修剪字符串的更合适的方式

剪裁字符串

 字符串trimData（字符串accessNum）{
        StringBuffer的SB =新的StringBuffer（）;
        尝试{
            如果（（accessNum =空）及！及（accessNum.length（）大于0））{
// Log.i（设置，accessNum +接入号码长度.....+ accessNum.length（））;
                accessNum = accessNum.trim（）;
                字节[] B = accessNum.getBytes（）;
                的for（int i = 0; I＆LT; b.length个;我++）{
                    的System.out.println（我+.....+ B [I]）;
                    如果（B [i]于大于0）{
                        sb.append（（char）的（B [I]））;
                    }
                }
// Log.i（Settigs，accessNum +裁剪......）;
            }}赶上（例外前）{            }
            返回sb.toString（）;
    }
 

解决方案

的 编辑的

使用等化器（由于Java 6）

 公共静态最终模式DIACRITICS_AND_FRIENDS
        = Pattern.compile（[\\\\ p {} InCombiningDiacriticalMarks \\\\ p {} ISLM \\\\ p {} IsSk] +）;
私有静态字符串stripDiacritics（字符串str）{
        海峡= Normalizer.normalize（STR，Normalizer.Form.NFD）;
        海峡= DIACRITICS_AND_FRIENDS.matcher（STR）.replaceAll（）;
        返回海峡;
}
 

和<一个href=\"http://stackoverflow.com/questions/1453171/n-n-n-or-remove-diacritical-marks-from-uni$c$c-char\">here和 是完整的解决方案。

如果你只想从一个字符串中删除所有非打印字符，请使用

  rawString.replaceAll（[^ \\\\ X20  -  \\\\ x7e]，）
 

参考：<一href=\"http://stackoverflow.com/questions/2608205/replace-special-characters-in-string-in-java\">replace在Java中和<字符串特殊字符href=\"http://stackoverflow.com/questions/5008422/how-to-remove-high-ascii-characters-from-string-like-in-java\">How从喜欢®字符串中删除高位ASCII字符，©，™Java中

I am reading data from xml. When I checked in eclipse console I found I am getting the whole data with some square boxes. Example If there is 123 in excel sheet i am getting 123 with some square boxes. I used trim() to avoid such things but didnot get success because trim() method trims only white spaces. But I found those characters have ASCII value -17, -20 .. I dont want to trim only white spaces I want to trim those square boxes also

So I have used the following method to trim those characters and I got success.

What is the more appropriate way of trimming a string

Trimming a string

String trimData(String accessNum){
        StringBuffer sb = new StringBuffer();
        try{
            if((accessNum != null) && (accessNum.length()>0)){
//              Log.i("Settings", accessNum+"Access Number length....."+accessNum.length());
                accessNum = accessNum.trim();
                byte[] b = accessNum.getBytes();
                for(int i=0; i<b.length; i++){
                    System.out.println(i+"....."+b[i]);
                    if(b[i]>0){
                        sb.append((char)(b[i]));
                    }
                }
//              Log.i("Settigs", accessNum+"Trimming....");
            }}catch(Exception ex){

            }
            return sb.toString();
    }

解决方案

Edited

use Normalizer (since java 6)

public static final Pattern DIACRITICS_AND_FRIENDS 
        = Pattern.compile("[\\p{InCombiningDiacriticalMarks}\\p{IsLm}\\p{IsSk}]+");


private static String stripDiacritics(String str) {
        str = Normalizer.normalize(str, Normalizer.Form.NFD);
        str = DIACRITICS_AND_FRIENDS.matcher(str).replaceAll("");
        return str;
}

And here and here are complete solution.

And if you only want to remove all non printable characters from a string, use

rawString.replaceAll("[^\\x20-\\x7e]", "")

Ref : replace special characters in string in java and How to remove high-ASCII characters from string like ®, ©, ™ in Java

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