python CGI:上传错误 [英] python CGI : upload error
问题描述
我使用的是Python 3.4版
I use Python version 3.4
这是python中的服务器源代码
and this is server source code in python
import io
from socket import *
import threading
import cgi
serverPort = 8181
serverSocket = socket(AF_INET, SOCK_STREAM)
serverSocket.bind(('', serverPort))
serverSocket.listen(5)
def serverHandle(connectionSocket, addr):
try:
message = connectionSocket.recv(1024)
if not message:
return
path = message.split()[1].decode('utf-8')
if path == '/':
connectionSocket.send(b'HTTP/1.1 200 OK\r\n')
connectionSocket.send(b'Content-type: text/html\r\n\r\n')
with open('upload.html', 'rb') as f:
connectionSocket.send(f.read())
elif path == '/upload':
header = message.split(b'\r\n\r\n')[0]
query = message.split(b'\r\n\r\n')[-1]
if not query:
return
fp = io.BytesIO(query)
form = cgi.FieldStorage(fp, environ={'REQUEST_METHOD':'POST', 'CONTENT_TYPE': 'multipart/form-data'})
f = open(form.filename, 'w')
f.write(form.file)
f.close()
connectionSocket.close()
except IOError:
connectionSocket.send('404 File Not Found\r\n\r\n'.encode('utf_8'))
connectionSocket.close()
while True:
connectionSocket, addr = serverSocket.accept();
threading._start_new_thread(serverHandle, (connectionSocket, addr))
serverSocket.close()
并在此处上传HTML源代码
and upload HTML source is here
<HTML>
<BODY>
<FORM ENCTYPE="multipart/form-data" ACTION="http://127.0.0.1:8181/upload" METHOD=POST>
File to process: <INPUT NAME="file" TYPE="file">
<INPUT TYPE="submit" VALUE="Send File">
</FORM>
</BODY>
</HTML>
我尝试将文件上传到服务器并将文件保存在目录中 但是会发生这样的错误
I try upload file to server and save file in directory but error is occurred like this
Unhandled exception in thread started by <function serverHandle at 0x000000000240CBF8>
Traceback (most recent call last):
File "C:\Users\Inwoo\Eclipse\workspace\WebServer\src\webserver1.py", line 36, in serverHandle
form = cgi.FieldStorage(fp, environ={'REQUEST_METHOD':'POST', 'CONTENT_TYPE': 'multipart/form-data'})
File "C:\Python34\lib\cgi.py", line 559, in __init__
self.read_multi(environ, keep_blank_values, strict_parsing)
File "C:\Python34\lib\cgi.py", line 681, in read_multi
raise ValueError('Invalid boundary in multipart form: %r' % (ib,))
ValueError: Invalid boundary in multipart form: b''
我听不懂这个问题吗?
有时消息查询为空！
所以我写了if not query: return，对吗?
如何接收上传的文件并将其保存在服务器中?
and how can I receive uploaded file and save them in server?
推荐答案
您需要不将查询拆分为尽可能多的换行符；里面可以嵌入换行符.在此处使用str.partition()代替:
You need to not split the query on as many newlines as you do; there can be embedded newlines in it. Use str.partition() instead here:
header, _, query = message.partition(b'\r\n\r\n')
您将不得不解析标题； Content-Type标头包含多部分边界； FieldStorage实例需要使用它来确定字段的开始和结束位置.
You'll have to parse the headers; the Content-Type header contains the multipart boundary; the FieldStorage instance needs this to determine where the fields begin and end.
import re
content_type = re.search(br'content-type:\s+(.*?)\r\n', header, flags=re.I).group(1)
form = cgi.FieldStorage(fp, environ={'REQUEST_METHOD':'POST', 'CONTENT_TYPE': content_type})
请注意，带有文件上传的HTTP消息很容易包含1024字节以上的内容；你只会读那么一点. 仅标题就可以轻松组成大部分邮件；我的浏览器发送了819个字节的标头，并将其保存在一个数据包中.然后，您的connectionSocket.recv(1024)呼叫将仅包含那些标题，并且您将需要仍然读取更多数据.
Take into account that a HTTP message with a file upload can easily contain much more that 1024 bytes; you only ever read that little. Just the headers can easily make up most of the message; my browser sends 819 bytes for the header and keeps that in one packet. Your connectionSocket.recv(1024) call will then contain just those headers and you'll need to read more data still.
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