如何在R中按列名称拆分数据帧? [英] How to split data frame by column names in R?
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问题描述
我在24小时内一直在寻找自己觉得很琐碎的问题(对我来说不是R的新手),但尚未结出硕果.所以请帮帮我.我有一个数据框,希望将其拆分为两个.这是数据的样子;
My 24 hours of search for what I feel is a trivial (Not for a newbie in R as I am) problem has not yet born fruits. So please help me out. I have a single data frame that I would wish to split into two. Here is how the data looks like;
d1 d2 d3 d4 p1 p2 p3 p4
30 40 20 60 1 3 2 5
20 50 40 30 3 4 1 5
40 20 50 30 2 3 1 4
这是我想要的样子;
$d
d1 d2 d3 d4
30 40 20 60
20 50 40 30
40 20 50 30
$p
p1 p2 p3 p4
1 3 2 5
3 4 1 5
2 3 1 4
我已经尝试过在线使用大多数命令和示例,但是它们似乎都在沿行拆分数据,例如:
I have tried to most of the commands and examples online but they all seem to be splitting data along rows such as in:
split(1:3, 1:2)
即使使用索引,我如何仍要从前四列中拆分出前四列呢?
How can I indicate even with the use of indexes that I want to split the first 4 columns from the last four?
推荐答案
使用sapply
和startsWith
:
sapply(c("d", "p"),
function(x) df[startsWith(names(df),x)],
simplify = FALSE)
# $d
# d1 d2 d3 d4
# 1 30 40 20 60
# 2 20 50 40 30
# 3 40 20 50 30
#
# $p
# p1 p2 p3 p4
# 1 1 3 2 5
# 2 3 4 1 5
# 3 2 3 1 4
tidyverse
的翻译:
library(tidyverse)
map(set_names(c("d", "p")),~select(df,starts_with(.x)))
# $d
# d1 d2 d3 d4
# 1 30 40 20 60
# 2 20 50 40 30
# 3 40 20 50 30
#
# $p
# p1 p2 p3 p4
# 1 1 3 2 5
# 2 3 4 1 5
# 3 2 3 1 4
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