pyqt5和多重继承 [英] pyqt5 and multiple inheritance

问题描述

我想创建一个新类，该类继承QWidget的两个子类.我知道在pyqt中不可能实现多重继承，但是如何在一个子类中同时拥有两个父类的属性?

I'd like to create a new class that inherits two subclasses of QWidget. I know multi-inheritance isn't possible in pyqt, but how could I manage to have the properties of both parent classes in one subclass?

我希望我能做的如下:

class A(QWidget):

    def __init__(self, widget, parent=None):
        widget.destroyed.connect(self.destroy_handler)

    @pyqtSlot()
    def destroy_handler(self):
        pass

class B (A, QStatusBar):
    def __init__(self, widget, parent=None):
        A.__init__(self, widget)
        QStatusBar.__init__(self, parent)

    @pyqtSlot()
    def destroyed_handler(self):
        print("Destroyed")

推荐答案

我终于找到了解决方法:首先，问题来自A和QStatusBar继承QWidget.我们无法更改QStatusBar，因此必须更改A. A不应继承QWidget:因此，让我们创建另一个类AInterface，如下所示:

I finally found how to do it: first of all, the problems came from A and QStatusBar inheriting QWidget. We can't change QStatusBar, so we must changer A. A shouldn't inherit QWidget: so let's create another class, AInterface, like that:

class AInterface(QObject):
    def __init__(self, a, parent=None)
        super().__init__(parent=parent)
        self.a = a
        self.connect_signal()

    def connect_signal(self, widget):
        widget.destroyed.connect(self.handler)

    @pyqtSlot()
    def handler(self):
        self.a.handler()

A现在具有以下实现:

A has now the following implementation:

class A:
    def __init__(self, widget):
        a.widget = widget
        a.interface = AInterface(self)

    def handler(self):
        pass

因此，现在我们可以创建不仅继承A而且继承任何QObject的子类，如下所示:

Thus, now we can create subclasses inheriting not only A but also any QObject, like this:

class B(QStatusBar, A):
    def __init__(self, widget, parent=None):
        QStatusBar.__init__(self, parent=parent, wiget=widget)
        A.__init__(self, widget)

    def handler(self):
        self.show('Destroyed', 3000)

请注意QStatusBar的构造函数中的widget=widget:如果我们未指定它，则会引发TypeError ...

Notice the widget=widget in the constructor of QStatusBar: if we don't specify it, a TypeError is thrown...

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