PyInstaller内置的Windows EXE失败并进行多处理 [英] PyInstaller-built Windows EXE fails with multiprocessing
问题描述
在我的项目中,我正在使用Python的multiprocessing
库在__main__中创建多个进程.使用PyInstaller 2.1.1将项目打包到单个Windows EXE中.
In my project I'm using Python's multiprocessing
library to create multiple processes in __main__. The project is being packaged into a single Windows EXE using PyInstaller 2.1.1.
我这样创建新流程:
from multiprocessing import Process
from Queue import Empty
def _start():
while True:
try:
command = queue.get_nowait()
# ... and some more code to actually interpret commands
except Empty:
time.sleep(0.015)
def start():
process = Process(target=_start, args=args)
process.start()
return process
在__main__中:
And in __main__:
if __name__ == '__main__':
freeze_support()
start()
不幸的是,当将应用程序打包到EXE中并启动它时,我在这行得到WindowsError
5或6(似乎是随机的):
Unfortunately, when packaging the application into an EXE and launching it, I get WindowsError
5 or 6 (seems random) at this line:
command = queue.get_nowait()
PyInstaller主页上的食谱声称,将应用程序打包为单个文件时,我必须修改代码以在Windows中启用多处理.
A recipe at PyInstaller's homepage claims that I have to modify my code to enable multiprocessing in Windows when packaging the application as a single file.
我在这里重现代码:
import multiprocessing.forking
import os
import sys
class _Popen(multiprocessing.forking.Popen):
def __init__(self, *args, **kw):
if hasattr(sys, 'frozen'):
# We have to set original _MEIPASS2 value from sys._MEIPASS
# to get --onefile mode working.
# Last character is stripped in C-loader. We have to add
# '/' or '\\' at the end.
os.putenv('_MEIPASS2', sys._MEIPASS + os.sep)
try:
super(_Popen, self).__init__(*args, **kw)
finally:
if hasattr(sys, 'frozen'):
# On some platforms (e.g. AIX) 'os.unsetenv()' is not
# available. In those cases we cannot delete the variable
# but only set it to the empty string. The bootloader
# can handle this case.
if hasattr(os, 'unsetenv'):
os.unsetenv('_MEIPASS2')
else:
os.putenv('_MEIPASS2', '')
class Process(multiprocessing.Process):
_Popen = _Popen
class SendeventProcess(Process):
def __init__(self, resultQueue):
self.resultQueue = resultQueue
multiprocessing.Process.__init__(self)
self.start()
def run(self):
print 'SendeventProcess'
self.resultQueue.put((1, 2))
print 'SendeventProcess'
if __name__ == '__main__':
# On Windows calling this function is necessary.
if sys.platform.startswith('win'):
multiprocessing.freeze_support()
print 'main'
resultQueue = multiprocessing.Queue()
SendeventProcess(resultQueue)
print 'main'
我对这个解决方案"感到沮丧的是,一个,它完全不知道要修补的是什么,其二,它以令人费解的方式写成,以致无法推断出哪个部分是解决方案,以及哪个是解决方案,这让我感到沮丧.只是一个例子.
My frustration with this "solution" is that, one, it's absolutely unclear what exactly it is patching, and, two, that it's written in such a convoluted way that it becomes impossible to infer which parts are the solution, and which are just an illustration.
任何人都可以在这个问题上分享一些看法,并提供洞察力,使在PyInstaller构建的单文件Windows可执行文件中实现多处理的项目中到底需要更改什么?
Can anyone share some light on this issue, and provide insight what exactly needs to be changed in a project that enables multiprocessing in PyInstaller-built single-file Windows executables?
推荐答案
显然,我们要做的只是提供一个Process
(和_Popen
)类,如下所示,并使用它代替multiprocessing.Process
.我已经纠正并简化了该类,使其仅可在Windows上使用,* ix系统可能需要不同的代码.
Apparently all we have to do is provide a Process
(and _Popen
) class as shown below, and use it instead of multiprocessing.Process
. I've corrected and simplified the class to work on Windows only, *ix systems might need different code.
出于完整性考虑,以下是上述问题的改编示例:
For the sake of completeness, here's the adapted sample from the above question:
import multiprocessing
from Queue import Empty
class _Popen(multiprocessing.forking.Popen):
def __init__(self, *args, **kw):
if hasattr(sys, 'frozen'):
os.putenv('_MEIPASS2', sys._MEIPASS)
try:
super(_Popen, self).__init__(*args, **kw)
finally:
if hasattr(sys, 'frozen'):
os.unsetenv('_MEIPASS2')
class Process(multiprocessing.Process):
_Popen = _Popen
def _start():
while True:
try:
command = queue.get_nowait()
# ... and some more code to actually interpret commands
except Empty:
time.sleep(0.015)
def start():
process = Process(target=_start, args=args)
process.start()
return process
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