Android的HTTP登录后 [英] Android Http Login Post

问题描述

我想通过anAndroid应用，使登录到我的网站。
出于某种原因，它总是无法登录。

I'm trying to make a login to my website via anAndroid app. For some reason it always fail to login.

下面是我对应用程序登录方法：

Here's my login method for the app:

private void login() {

         //this method returns false
         HttpClient httpclient = new DefaultHttpClient();  
         HttpPost httppost = new HttpPost("http://mysite.com/mobileauth.php");
         JSONObject jsonObject = new JSONObject();

           try {  

               List nameValuePairs = new ArrayList(2);  
               jsonObject.put("username", "user1");
               jsonObject.put("password", "12345");

               nameValuePairs.add(new BasicNameValuePair("jsonString", jsonObject.toString()));               

               httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
               HttpResponse response = httpclient.execute(httppost);



               String responseStr = org.apache.http.util.EntityUtils.toString(response.getEntity());
               statusText.setText(responseStr);

           } catch (ClientProtocolException e) {  
               statusText.setText(e.toString());
           } catch (IOException e) {   
               statusText.setText(e.toString());
           } catch (JSONException e) {
               statusText.setText(e.toString());
           }
}

我创建了移动设备登录特定的文件如Android。

I created a specific file for mobile device login such as Android.

下面是在服务器上我的认证文件：

Here's my authentication file on the server:

$host="*"; // Host name 
$username="*"; // Mysql username 
$password="*"; // Mysql password 
$tbl_name="users"; // Table name
$db_name="database";

$link = mysql_connect($host, $username, $password) or die("Connection Error"); 
$db = mysql_select_db("$db_name")or die("Connection Error");

$myusername = $_REQUEST['username']; 
$mypassword = $_REQUEST['password'];

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' AND paswd='$mypassword'";
$result = mysql_query($sql);

$count = mysql_num_rows($result);

if ($count == 1) {
    $timeUpdateQuesry="UPDATE users SET lastLogin=Now() WHERE username='$myusername' AND paswd='$mypassword'";
    mysql_query($timeUpdateQuesry);

    echo("true");
} else {
    //happend without leaving page
    echo ("false");
}

由于某种原因，我总是假我的状态TextView中。

For some reason I always get false in my status TextView.

我将AP preciate任何帮助

I'll appreciate any help

谢谢，

推荐答案

从Android code取出所有的JSON。你不接受它作为JSON在PHP端，所以这可能是一个根本原因。该namevaluepairs中应该工作正常。

Remove all the JSON from your android code. You're not receiving it as JSON on the PHP side, so this is probably a root cause. The NameValuePairs should work fine.

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