为什么在Python的线程处理中出现TypeError [英] Why do I get TypeError in Threading in Python

问题描述

我有以下代码，这些代码基于我在SO上找到的示例，但是当我运行它时出现错误.请帮忙，我确定它非常简单:

I've got the following code which is based off an example i found here on SO, but when i run it i get an error. Please help, i'm sure its very simple:

def listener(port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    sock.bind(('',port))
    sock.settimeout(1) # n second(s) timeout
    try:
        while True:
            data, addr = sock.recvfrom(1024)
            print data
    except socket.timeout:
        print 'Finished'

def startListenerThread(port):
    threading.Thread(target=listener, args=(port)).start()

我得到的错误是:

Exception in thread Thread-1:
Traceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/threading.py", line 522, in __bootstrap_inner
    self.run()
  File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/threading.py", line 477, in run
    self.__target(*self.__args, **self.__kwargs)
TypeError: listener() argument after * must be a sequence, not int

推荐答案

错误来自以下行:

threading.Thread(target=listener, args=(port)).start()

args参数必须是一个序列，我想您的意图是使用元组，但是将单个值包装在括号中并不能实现这一点.这是您需要将其更改为:

The args parameter needs to be a sequence, I think your intention is to use a tuple, but wrapping a single value in parentheses does not accomplish this. Here is what you need to change it to:

threading.Thread(target=listener, args=(port,)).start()

下面是一个显示差异的简单示例:

Here is a simple example showing the difference:

>>> (100)  # this is just value 100
100
>>> (100,) # this is a tuple containing the value 100
(100,)

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