Python线程错误-必须是可迭代的，而不是int [英] Python threading error - must be an iterable, not int

问题描述

我正在尝试计算数据帧中第一列和其他列(第一列和第二列，第一列和第三列等)之间回归的滚动r平方，但是当我尝试线程化时，它一直告诉我该错误

I'm trying to calculate rolling r-squared of regression among first column and other columns in a dataframe (first column and second, first column and third etc.) But when I try threading, it kept telling me the error that

TypeError:*之后的ParallelRegression()参数必须是可迭代的，而不是int.

TypeError: ParallelRegression() argument after * must be an iterable, not int".

我想知道如何解决此问题?非常感谢！

I'm wondering how do I fix this? Thanks very much!

import threading

totalThreads=3 #three different colors
def ParallelRegression(threadnum):
    for i in range(threadnum):
        res[:,i]=sm.OLS(df.iloc[:,0], df.iloc[:,i+1]).fit().rsquared
threads=[]
for threadnum in range(totalThreads):
    t=threading.Thread(target=ParallelRegression,args=(threadnum))
    threads.append(t)
    t.start()
for threadnum in range(totalThreads):
    threads[threadnum].join()

在下面链接的图片中查看数据(df)的摘要:

See a summary of the data (df) in the picture linked below:

推荐答案

threading.Thread类需要一个可迭代的参数作为args参数.您要传递的args=(threadnum)是单个int对象，您需要传递一些可迭代的对象，该对象将允许多个arg，即使您只想传递一个arg.

threading.Thread class needs an iterable of arguments as the args parameter. You're passing args=(threadnum) which is a single int object, you need to pass some iterable object that would allow multiple args, even when you only want to pass one arg.

args=[threadnum]可以工作，因为这使得list可以迭代.

args=[threadnum] would work, because that makes a list which is iterable.

这篇关于Python线程错误-必须是可迭代的，而不是int的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！