Python线程中断睡眠 [英] Python threading interrupt sleep

问题描述

Python中有没有办法在线程休眠时中断线程? (就像我们在Java中一样)

Is there a way in python to interrupt a thread when it's sleeping? (As we can do in java)

我正在寻找类似的东西.

I am looking for something like that.

  import threading
  from time import sleep

  def f():
      print('started')
  try:
      sleep(100)
      print('finished')
  except SleepInterruptedException:
      print('interrupted')

t = threading.Thread(target=f)
t.start()

if input() == 'stop':
    t.interrupt()

线程正在休眠100秒，如果我键入停止"，则会中断

The thread is sleeping for 100 seconds and if I type 'stop', it interrupts

推荐答案

如何使用条件对象: https://docs.python.org/2/library/threading.html#condition-objects

使用wait( timeout )代替sleep().要中断"，请调用notify().

Instead of sleep() you use wait(timeout). To "interrupt" you call notify().

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