命令不同步；您现在不能运行此命令 [英] Commands out of sync; you can't run this command now

问题描述

我正在尝试执行我的PHP代码，该代码通过mysqli调用两个MySQL查询，并收到错误消息:命令不同步；您现在不能运行此命令".

I am trying to execute my PHP code, which calls two MySQL queries via mysqli, and get the error "Commands out of sync; you can't run this command now".

这是我正在使用的代码

<?php
$con = mysqli_connect("localhost", "user", "password", "db");
if (!$con) {
    echo "Can't connect to MySQL Server. Errorcode: %s\n". Mysqli_connect_error();
    exit;
}
$con->query("SET NAMES 'utf8'");
$brand ="o";
$countQuery = "SELECT ARTICLE_NO FROM AUCTIONS WHERE upper(ARTICLE_NAME) LIKE % ? %";
if ($numRecords = $con->prepare($countQuery)) {
    $numRecords->bind_param("s", $brand);
    $numRecords->execute();
    $data = $con->query($countQuery) or die(print_r($con->error));
    $rowcount = $data->num_rows;
    $rows = getRowsByArticleSearch("test", "Auctions", " ");
    $last = ceil($rowcount/$page_rows);
}  else {

print_r($con->error);
}
foreach ($rows as $row) {
    $pk = $row['ARTICLE_NO'];
    echo '<tr>' . "\n";
    echo '<td><a href="#" onclick="updateByPk(\'Layer2\', \'' . $pk . '\')">'.$row['USERNAME'].'</a></td>' . "\n";
    echo '<td><a href="#" onclick="updateByPk(\'Layer2\', \'' . $pk . '\')">'.$row['shortDate'].'</a></td>' . "\n";
    echo '<td><a href="#" onclick="deleterec(\'Layer2\', \'' . $pk . '\')">DELETE RECORD</a></td>' . "\n";
    echo '</tr>' . "\n";
}
function getRowsByArticleSearch($searchString, $table, $max) {
    $con = mysqli_connect("localhost", "user", "password", "db");
    $recordsQuery = "SELECT ARTICLE_NO, USERNAME, ACCESSSTARTS, ARTICLE_NAME, date_format(str_to_date(ACCESSSTARTS, '%d/%m/%Y %k:%i:%s'), '%d %m %Y' ) AS shortDate FROM AUCTIONS WHERE upper(ARTICLE_NAME) LIKE '%?%' ORDER BY str_to_date(ACCESSSTARTS, '%d/%m/%Y %k:%i:%s')" . $max;
    if ($getRecords = $con->prepare($recordsQuery)) {
        $getRecords->bind_param("s", $searchString);
        $getRecords->execute();
        $getRecords->bind_result($ARTICLE_NO, $USERNAME, $ACCESSSTARTS, $ARTICLE_NAME, $shortDate);
        while ($getRecords->fetch()) {
            $result = $con->query($recordsQuery);
            $rows = array();
            while($row = $result->fetch_assoc()) {
                $rows[] = $row;
            }
            return $rows;
        }
    }
}

我已经尝试阅读此书，但是我不确定该怎么做.我已经阅读了有关存储结果和免费结果的信息，但是使用它们时并没有什么区别.我不确定此错误的确切原因，并想知道其原因以及如何解决.

I have tried reading up on this, but I am unsure of what to do. I have read about store result and free result, however these have made no difference when using them. I am unsure at exactly which point this error is being caused, and would like to know why it is being caused, and how to fix it.

按照我的调试语句进行操作，由于'% ? %'附近的sql语法错误，甚至没有输入countQuery的第一个if循环.但是，如果我只是选择*而不是尝试根据LIKE子句进行限制，则仍然会出现命令不同步错误.

Going by my debug statements, the first if loop for countQuery is not even being entered, because of an error in my sql syntax near near '% ? %'. However if I just select * instead of trying to limit based on a LIKE clause, I still get the command out of sync error.

推荐答案

您不能同时进行两个查询，因为mysqli默认情况下使用无缓冲查询(对于准备好的语句；对于香草mysql_query则相反).您可以将第一个取入数组并循环遍历，也可以告诉mysqli缓冲查询(使用

You can't have two simultaneous queries because mysqli uses unbuffered queries by default (for prepared statements; it's the opposite for vanilla mysql_query). You can either fetch the first one into an array and loop through that, or tell mysqli to buffer the queries (using $stmt->store_result()).

有关详情，请参见此处.

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