以整数形式获取MySQL中两个日期之间的年份差异 [英] Get difference in years between two dates in MySQL as an integer

问题描述

我正在尝试计算数据库中一个人的年龄.
让我们假设有一个简单的表:

I am trying to calculate how old is a person in a database.
Let's suppose to have this simple table:

student(id, birth_date);

其中id是主键(表实际上比较复杂，但我已经对其进行了简化).
我想让一个人多大年龄:

Where id is the primary key (truly the table is more complex but I have simplified it).
I want to get how much old is a single person:

select id, datediff(curdate(),birth_date) 
from student

但是它返回的结果是几天而不是几年.我可以将其除以365:

But it returns a result in days, and not in years.I could divide it by 365:

select id, datediff(curdate(),birth_date) / 365
from student

但是它返回一个浮点值，我想要一个整数.
这样我就可以计算出年份:

But it returns a floating point value, and I want an integer.
So I could calculate the years:

select id, year(curdate())-year(birth_date) 
from student

但是有一个问题:例如现在是5月，如果一个人战争发生在1970年6月，那么他仍然是31岁而不是32岁，但表达式返回32.
我无法摆脱这个问题，有人可以帮助我吗?

But there is a problem: for instance now is May, if a person war born in June, 1970 he has still 31 years and not 32, but the expression returns 32.
I can't come out of this problem, can someone help me?

推荐答案

对于遇到此问题的任何人:

For anyone who comes across this:

另一种可以做到的方式是:

another way this can be done is:

SELECT TIMESTAMPDIFF(YEAR, date_of_birth, CURDATE()) AS difference FROM student

对于月份差异，将YEAR替换为MONTH，对于几天，将YEAR替换为DAY

For differences in months, replace YEAR with MONTH, and for days replace YEAR with DAY

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