MySQL Levenshtein [英] MySQL Levenshtein

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本文介绍了MySQL Levenshtein的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试创建一个MySQL函数来计算levenshtein距离.我发现了一个看起来很接近我所需功能的函数,但是它到处都会抛出错误-我是MySQL函数的新手,所以我不知道哪里出了问题?

I'm trying to create a MySQL function for calculating the levenshtein distance. I found a function which looked pretty close to what I need, however it keeps throwing errors everywhere - I am new to MySQL functions so I have no idea what is wrong?

这是函数:

DELIMITER $$

CREATE FUNCTION LEVENSHTEIN( s1 CHAR(255), s2 CHAR(255)) 
RETURNS int(3) 
DETERMINISTIC
BEGIN
    DECLARE s1_len, s2_len, i, j, c, c_temp, cost INT;
    DECLARE s1_char CHAR(255);
    DECLARE cv0, cv1 CHAR(255);

    SET s1_len = LENGTH(s1);
    SET s2_len = LENGTH(s2);
    SET cv1 = 0x00;
    SET j = 1;
    SET i = 1;
    SET c = 0;

    IF s1 = s2 THEN
        RETURN 0;
    ELSE IF s1_len = 0 THEN
        RETURN s2_len;
    ELSE IF s2_len = 0 THEN
        RETURN s1_len;
    ELSE
        WHILE j <= s2_len DO 
          SET c = c + 1; 
          IF s1_char = SUBSTRING(s2, j, 1) THEN  
            SET cost = 0; ELSE SET cost = 1; 
          END IF; 
          SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost; 
                SET c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1;
                IF c > c_temp THEN
                    SET c = c_temp;
                END IF;
                SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1;
            END WHILE;
            SET cv1 = cv0, i = i + 1;
        END WHILE;
    END IF;
    RETURN c;
END$$

DELIMITER ;

这是错误(到目前为止).

And here is the error (so far).

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHILE; END IF; RETURN c; END' at line 36

编辑:可以在此处找到原始代码>

Original code can be found here

推荐答案

在创建函数之前不要忘记更改delimiter.

don't forget to change the delimiter before creating the function.

DELIMITER $$

CREATE FUNCTION LEVENSHTEIN( s1 CHAR(255), s2 CHAR(255)) 
RETURNS int(3) 
DETERMINISTIC
BEGIN
    DECLARE s1_len, s2_len, i, j, c, c_temp, cost INT;
    DECLARE s1_char CHAR(255);
    DECLARE cv0, cv1 CHAR(255);

    SET s1_len = LENGTH(s1);
    SET s2_len = LENGTH(s2);
    SET cv1 = 0x00;
    SET j = 1;
    SET i = 1;
    SET c = 0;

    IF s1 = s2 THEN
        RETURN 0;
    ELSE IF s1_len = 0 THEN
        RETURN s2_len;
    ELSE IF s2_len = 0 THEN
        RETURN s1_len;
    ELSE
        WHILE j <= s2_len DO 
          SET c = c + 1; 
          IF s1_char = SUBSTRING(s2, j, 1) THEN  
            SET cost = 0; ELSE SET cost = 1; 
          END IF; 
          SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost; 
                SET c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1;
                IF c > c_temp THEN
                    SET c = c_temp;
                END IF;
                SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1;
            END WHILE;
            SET cv1 = cv0, i = i + 1;
        END WHILE;
    END IF;
    RETURN c;
END$$

DELIMITER ;

这篇关于MySQL Levenshtein的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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