PHP/MySQL的递归递归菜单 [英] Hierarchical recursion menu with PHP/MySQL

问题描述

(希望)对某些人来说，这是一个非常简单的问题.

This should (hopefully) be a pretty easy question for some of you to answer.

我有一个来自mySQL数据库的递归菜单，现在我的主要问题是:

I have a working Recursive menu from a mySQL database, now my main problem is:

创建URL的最佳方法是什么?我希望输入每行的标题，例如/eggs/milk/bacon/.鸡蛋的等级为0，例如:鸡蛋0，牛奶1，培根2.关于如何动态输出此内容的任何想法?

What is the best way to create the URL? I would prefer to bring in the title of each row like /eggs/milk/bacon/. Eggs being level 0 like: eggs-0, milk-1, bacon-2. Any ideas on how to dynamicly output this?

对于"cletus"所说的这个问题，我几乎同意了: PHP/MySQL-建立导航菜单层次结构

I am pretty much going for what "cletus" said a few comments down on this question: PHP/MySQL - building a nav menu hierarchy

但是我需要更多有关如何执行操作的解释.

But I need a bit more explanation on how to do it.

推荐答案

除非您计划经常修改菜单树，否则为每个菜单项预先存储所需的分层URL可能是最简单的(对于运行时解析， ).

Unless you plan to modify your menu tree often, pre-storing the required hierarchical URL for each menu item is probably the easiest (for run-time resolution that is).

如果您希望树可以经常修改，可以说-通过Web界面，那么每次阅读菜单时都会更容易生成路径，如下所示:

If you expect the tree to be modified often enough, lets say - through a web interface, then it would be easier to generate the paths every time you read the menu, something like this:

 id | name   | parent
----+--------+-------
 0  | eggs   | NULL
 1  | milk   | 0
 2  | bacon  | 1
 3  | tomato | 0
 4  | lettuce| 1

foreach (query("SELECT * FROM menu ORDER BY parent ASC") as $row) {
  $menuitem = array_merge(array(), $row);
  $menuLookup[$menuitem['id']] &= $menuitem;
  if ($menuitem['parent'] == null) {
    $menuitem['path'] = "/" . $menuitem['name'];
    $menu[] &= $menuitem[];
  } else {
    $parent &= $menuLookup[$menuitem['parent']];
    $menuitem['path'] = $parent['path'] . "/" . $menuitem['name'];
    $parent['menu'][] &= $menuitem;
  }
}

我还没有调试过这段代码，只是测试了它的正确性;-)

I haven't debugged this code, only tested it for correctness ;-)

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