MySQL在每个唯一值的首次出现时选择行 [英] MySQL Select rows on first occurrence of each unique value
问题描述
假设您有下表(这里感兴趣的列是cid
):
Let's say you have the following table (the column of interest here is cid
):
+-----+-------+-------+-------+---------------------+--------------+
| cid | pid | rid | clink | time | snippet |
+-----+-------+-------+-------+---------------------+--------------+
| 155 | 11222 | 1499 | 1137 | 2012-08-22 03:05:06 | hi |
| 138 | 11222 | 241 | 1136 | 2012-08-21 05:25:00 | again |
| 138 | 11222 | 241 | 1135 | 2012-08-21 05:16:40 | hi |
| 155 | 11222 | 1499 | 1134 | 2012-08-21 05:11:00 | hi cute |
| 140 | 11222 | 11223 | 1133 | 2012-08-21 05:05:18 | hi |
| 154 | 11222 | 565 | 1132 | 2012-08-21 05:04:47 | 7 |
| 153 | 11222 | 272 | 1131 | 2012-08-21 05:04:41 | 6 |
| 146 | 11222 | 362 | 1130 | 2012-08-21 05:04:33 | 5 |
| 152 | 11222 | 364 | 1129 | 2012-08-21 05:04:27 | 4 |
| 151 | 11222 | 390 | 1128 | 2012-08-21 05:04:22 | 3 |
| 150 | 11222 | 333 | 1127 | 2012-08-21 05:04:16 | 2 |
| 148 | 11222 | 268 | 1126 | 2012-08-21 05:04:10 | 1 |
| 140 | 11222 | 11223 | 1125 | 2012-08-21 04:59:57 | hi sir |
| 147 | 11222 | 283 | 1123 | 2012-08-21 03:29:55 | yo |
| 140 | 11222 | 11223 | 1121 | 2012-08-21 02:12:13 | hello! |
| 139 | 11222 | 249 | 1120 | 2012-08-21 02:11:53 | hi :) |
| 140 | 11222 | 11223 | 1119 | 2012-08-21 02:11:26 | hi :) |
| 140 | 11222 | 11223 | 1118 | 2012-08-21 02:11:08 | hi too |
| 139 | 11222 | 249 | 1117 | 2012-08-21 02:11:00 | :P |
| 139 | 11222 | 249 | 1116 | 2012-08-21 02:10:57 | hi |
| 139 | 11222 | 249 | 1115 | 2012-08-21 02:10:51 | helo |
| 139 | 11222 | 249 | 1114 | 2012-08-21 02:06:19 | hi |
| 139 | 11222 | 249 | 1113 | 2012-08-21 02:05:45 | hi baby |
| 139 | 11222 | 249 | 1112 | 2012-08-21 02:05:00 | hi |
| 139 | 11222 | 249 | 1111 | 2012-08-21 02:04:41 | hi |
| 140 | 11222 | 11223 | 1110 | 2012-08-21 02:04:26 | hi |
| 140 | 11222 | 11223 | 1108 | 2012-08-21 01:47:40 | hey :) |
| 139 | 11222 | 249 | 1107 | 2012-08-21 01:44:43 | hi |
| 138 | 11222 | 241 | 1106 | 2012-08-21 01:44:11 | hi |
| 138 | 11222 | 241 | 1105 | 2012-08-21 01:09:20 | conv 1 msg 1 |
+-----+-------+-------+-------+---------------------+--------------+
如何仅提取每个cid
的第一个匹配项?结果表将是:
How to extract only the first occurrence of each cid
? The resulting table would be:
+-----+-------+-------+-------+---------------------+--------------+
| cid | pid | rid | clink | time | snippet |
+-----+-------+-------+-------+---------------------+--------------+
| 155 | 11222 | 1499 | 1137 | 2012-08-22 03:05:06 | hi |
| 138 | 11222 | 241 | 1136 | 2012-08-21 05:25:00 | again |
| 140 | 11222 | 11223 | 1133 | 2012-08-21 05:05:18 | hi |
| 154 | 11222 | 565 | 1132 | 2012-08-21 05:04:47 | 7 |
| 153 | 11222 | 272 | 1131 | 2012-08-21 05:04:41 | 6 |
| 146 | 11222 | 362 | 1130 | 2012-08-21 05:04:33 | 5 |
| 152 | 11222 | 364 | 1129 | 2012-08-21 05:04:27 | 4 |
| 151 | 11222 | 390 | 1128 | 2012-08-21 05:04:22 | 3 |
| 150 | 11222 | 333 | 1127 | 2012-08-21 05:04:16 | 2 |
| 148 | 11222 | 268 | 1126 | 2012-08-21 05:04:10 | 1 |
| 147 | 11222 | 283 | 1123 | 2012-08-21 03:29:55 | yo |
| 140 | 11222 | 11223 | 1121 | 2012-08-21 02:12:13 | hello! |
| 139 | 11222 | 249 | 1120 | 2012-08-21 02:11:53 | hi :) |
+-----+-------+-------+-------+---------------------+--------------+
推荐答案
mysql为此有一个骗子":
mysql has a "cheat" for this:
select *
from mytable
group by cid;
这就是您所需要的,因为在mysql中,它允许您不聚集非分组列(其他数据库会引发语法错误),在这种情况下,它仅输出第一次出现的列每个分组值的.请注意,尽管这不能保证确定首次"出现的方式(这只是读取行的方式)
That's all you need, because in mysql it allows you to not aggregate the non-grouped-by columns (other databases would throw a syntax error), in which case it outputs only the first occurrence of each group-by value(s). Note though that this won't guarantee the way in which the "first" occurrence is determined (it will be just how the rows are read in)
如果您想首先出现特殊,请先进行排序,然后应用分组欺骗:
If you want a particular first occurrence, sort first, then apply the group-by cheat:
select *
from (
-- order by the "time" column descending to get the "most recent" row
select * from mytable order by time desc
) x
group by cid
这篇关于MySQL在每个唯一值的首次出现时选择行的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!