在mysql中选择连续的记录块 [英] Selecting contiguous block of records in mysql

问题描述

我在MySql 5中有一个电话号码表.简单的结构是

I have a table in MySql 5 of phone numbers. The simple structure is

Accounts
id varchar(32) NOT NULL

记录如下

27100070000
27100070001
27100070002
27100070003
27100070004
27100070005
27100070008
27100070009
27100070012
27100070015
27100070016
27100070043

我需要对这些数据进行排序，并将连续的数字块分组为数字范围.我愿意在C#LINQ中实现该解决方案，但是服务器端MySql是一等奖.在MySql中有没有一种方法可以汇总这些数据，以便输出如下所示?

I need to sort through this data and group contiguous blocks of numbers into number ranges. I'm open to implementing the solution in C# LINQ but server-side MySql is first prize. Is there a way in MySql to get this data summarised so that the output is as below?

Start       | End
-------------------------
27100070000 | 27100070005
27100070008 | 27100070009
27100070012 | 27100070015
27100070016 | NULL
27100070043 | NULL

推荐答案

有一个简单的技巧可以将连续的条目折叠成一个组.如果按(row_number-entry)分组，则连续的条目将以同一组结束.这是一个演示我的意思的示例:

There is a simple trick to collapse consecutive entries into a single group. If you group by (row_number - entry), the entries that are consecutive will end up in the same group. Here is an example demonstrating what I mean:

查询:

SELECT phonenum, @curRow := @curRow + 1 AS row_number, phonenum - @curRow
from phonenums p
join (SELECT @curRow := 0) r

结果:

|    PHONENUM | ROW_NUMBER | PHONENUM - @CURROW |
-------------------------------------------------
| 27100070000 |          1 |        27100069999 |
| 27100070001 |          2 |        27100069999 |
| 27100070002 |          3 |        27100069999 |
| 27100070003 |          4 |        27100069999 |
| 27100070004 |          5 |        27100069999 |
| 27100070005 |          6 |        27100069999 |
| 27100070008 |          7 |        27100070001 |
| 27100070009 |          8 |        27100070001 |
| 27100070012 |          9 |        27100070003 |
| 27100070015 |         10 |        27100070005 |
| 27100070016 |         11 |        27100070005 |
| 27100070040 |         12 |        27100070028 |

请注意，连续的条目都对PHONENUM - @CURROW具有相同的值.如果我们在该列上进行分组，然后选择分钟和分钟每个组的最大值，您都有摘要(一个例外:如果需要START = END，则可以用NULL替换END值):

Notice how the entries that are consecutive all have the same value for PHONENUM - @CURROW. If we group on that column, and select the min & max of each group, you have the summary (with one exception: you could replace the END value with NULL if START = END if that's a requirement):

查询:

select min(phonenum), max(phonenum) from
(
  SELECT phonenum, @curRow := @curRow + 1 AS row_number
  from phonenums p
  join (SELECT @curRow := 0) r
) p
group by phonenum - row_number

结果:

| MIN(PHONENUM) | MAX(PHONENUM) |
---------------------------------
|   27100070000 |   27100070005 |
|   27100070008 |   27100070009 |
|   27100070012 |   27100070012 |
|   27100070015 |   27100070016 |
|   27100070040 |   27100070040 |

演示: http://www.sqlfiddle.com/#!2/59b04/5

这篇关于在mysql中选择连续的记录块的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！