无法在MySQLi PHP中将对象转换为字符串 [英] Object can't be converted to a string in MySQLi PHP
问题描述
可捕获的致命错误:在第20行的C:\ xampp \ htdocs \ xxx \ dash.php中,类mysqli_result的对象无法转换为字符串
Catchable fatal error: Object of class mysqli_result could not be converted to string in C:\xampp\htdocs\xxx\dash.php on line 20
我是相当新的人,并且是一名老式的编码员,仅使用mysql_result来获取此类数据,我不知道该如何处理.我有一个class->功能设置.
I am quite fairly new, and being a old-school coder, simply using mysql_result to grab such data, I am unaware of how to go about this. I have a class->function setup.
dash.php的第20行包含:
Line 20 of dash.php contains:
echo $user->GetVar('rank', 'Liam', $mysqli);
该函数是:
function GetVar($var, $username, $mysqli)
{
$result = $mysqli->query("SELECT " . $var . " FROM users WHERE username = '" . $username . "' LIMIT 1");
return $result;
$result->close();
}
现在,据我了解,我打算将$ result转换为字符串,但是我并不完全知道该怎么做.我尝试使用一些方法,但无济于事.因此,我来到社区希望获得答案,我也环顾四周,但注意到所有其他线程都在请求num_rows,而我只是想从查询select中获取字符串.
Now, to my understanding, I am meant to convert $result into a string, but I am not fully aware of how to do so. I've tried using a few methods, but to no avail. So I've come to the community to hopefully get a answer, I've also looked around but noticed that all other threads are asking for num_rows, while I just want to grab the string from the query select.
推荐答案
在回显结果之前,您必须先获取它.粗略的例子:
You have to fetch it first before echoing the results. Rough Example:
function GetVar($var, $username, $mysqli) {
// make the query
$query = $mysqli->query("SELECT ".$var." FROM users WHERE username = '".$username."' LIMIT 1");
$result = $query->fetch_assoc(); // fetch it first
return $result[$var];
}
然后使用您的功能:
echo $user->GetVar('rank', 'Liam', $mysqli);
重要说明:由于您是刚开始,请检查准备的语句.不要在查询中直接附加用户输入.
Important Note: Since you're starting out, kindly check about prepared statements. Don't directly append user input on your query.
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