具有2个条件的Doctrine2左联接 [英] Doctrine2 LEFT JOIN with 2 conditions

问题描述

我正在尝试通过ID查找产品"，并在两种情况下将其所有照片"连接起来:区域设置和活动状态.

I'm trying to find a 'Product' by ID, and to left join all it's 'Photo' on two conditions: the locale AND the active state.

这是我的QueryBuilder:

Here's my QueryBuilder :

$queryBuilder = $this->createQueryBuilder('p')
            ->select('p, photos, photoTranslation')
            ->leftJoin('p.photos', 'photos')
            ->leftJoin('photos.translations', 'photoTranslation')
            ->where('p.id = :id')
            ->andWhere('(photoTranslation.locale = :locale OR photoTranslation.locale IS NULL)')
            ->andWhere('(photoTranslation.active = :active OR photoTranslation.active IS NULL)')
            ->setParameters(array(
                'id' => $id
                'locale' => $this->getLocale(),
                'active' => true
             ));

在没有照片或有活动照片的情况下，它可以正常工作，但在没有活动照片的情况下，则不能正常工作，因为它不符合两个条件之一.

It works fine when there are no Photos or when there are ACTIVE photos, but not when there's an inactive Photo because it doesn't match one of the two conditions.

如果我仅使用一种条件，例如仅使用语言环境部分，它就可以正常工作:

If I use only one condition, for instance only the locale part, it works fine :

$queryBuilder = $this->createQueryBuilder('p')
            ->select('p, photos, photoTranslation')
            ->leftJoin('p.photos', 'photos')
            ->leftJoin('photos.translations', 'photoTranslation')
            ->where('p.id = :id')
            ->andWhere('(photoTranslation.locale = :locale OR photoTranslation.locale IS NULL)')
            ->setParameters(array(
                'id' => $id
                'locale' => $this->getLocale()
             ));

现在，我循环查看这些结果并取消设置所有不活动的照片...，但我想在QueryBuilder中使用一种干净的方法.

For now, I loop on theses results and unset all inactive Photos... but I'd like a clean way to do in the QueryBuilder.

我还尝试将条件放在LEFT JOIN子句上:

I also tried to put the conditions on the LEFT JOIN clause :

->leftJoin('photo.translations', 'phototTranslation', Doctrine\ORM\Query\Expr\JOIN::WITH, 'photoTranslation.locale = :locale AND photoTranslation.active = :active')

但是即使它不活动，它也总是返回照片.

But it always returns the Photo, even if it's inactive.

推荐答案

对此问题的解决方案可能是:

For this problem a solution may be:

$em = $this->getEntityManager();
$qb = $em->createQueryBuilder();
$qb
    ->select('p', 'pp')
    ->from('Product', 'p')
    ->leftJoin('p.photos', 'pp')
    ->leftJoin('pp.translations', 'ppt', Doctrine\ORM\Query\Expr\Join::WITH, $qb->expr()->andX(
        $qb->expr()->eq('ppt.locale', ':locale'),
        $qb->expr()->eq('ppt.active', ':active')
    ))
    ->where('p.id', ':productId')
    ->setParameters(
        array(
            'productId', $productId,
            'active', $active,
            'locale', $locale
        )
    );

    $query = $qb->getQuery();
    return $query->getResult(); // or ->getSingleResult();

注意:此示例是在Symfony2(2.3)实体存储库中执行此操作的方法

NOTE: this example is the way to do it in Symfony2 (2.3) entity repository

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